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我是OOP和一般編程的新手。我在如何將東西放在父類中並從其他類和main中調用它們時遇到了問題。在父類中插入數組列表以覆蓋子類
我在main中有以下arraylist創建者，但覺得是真正的OOP，這些應該在父類和子類中，並從main調用。這是否正確，有人可以幫助我解決這個問題。
如何獲取父類中的數組列表，然後從main中正確調用它？
這是我的主：
package ooo1;
import java.util.ArrayList;
import java.util.Scanner;
public class ContactList {
public static void main(String[] args) {
Scanner input1 = new Scanner(System.in);
int type = 0;
while(type != 5){
System.out.println("Please select an option:");
System.out.println("Personal Contact: Enter 1");
System.out.println("Business Contact: Enter 2");
System.out.println("Display Personal Contacts: Enter 3");
System.out.println("Display Business Contacts: Enter 4");
System.out.println("5 to quit");
type = input1.nextInt();
if(type == 5){
System.out.println("Goodbye");
break;
}
ArrayList<Contact> contacts = new ArrayList<Contact>();
Scanner input = new Scanner(System.in);
System.out.println("Please enter ContactId : ");
String contactId = input.nextLine();
System.out.println("Please enter First Name : ");
String firstName = input.nextLine();
System.out.println("Please enter Last Name : ");
String lastName = input.nextLine();
System.out.println("Please enter Address : ");
String address = input.nextLine();
System.out.println("Please enter Phone Number : ");
String phoneNumber = input.nextLine();
System.out.println("Please enter Email Address : ");
String emailAddress = input.nextLine();
if(type == 1){
System.out.println("Please enter Birthday: ");
String dateofBirth = input.nextLine();
Contact pcontact = new PersonalContact(contactId, firstName, lastName, address, phoneNumber, emailAddress, dateofBirth);
contacts.add(pcontact);
}
else if(type == 2){
System.out.println("Please enter Job Title: ");
String jobTitle = input.nextLine();
System.out.println("Please enter Organization: ");
String organization = input.nextLine();
Contact bcontact = new BusinessContact(contactId, firstName, lastName, address, phoneNumber, emailAddress, jobTitle, organization);
contacts.add(bcontact);
}
}
}
}
這就是我對父類：
package ooo1;
import java.util.ArrayList;
import java.util.Scanner;
public abstract class Contact {
String contactId;
String firstName;
String lastName;
String address;
String phoneNumber;
String emailAddress;
public Contact(String contactId,String firstName,String lastName, String address, String phoneNumber, String emailAddress)
{
this.contactId = contactId;
this.firstName = firstName;
this.lastName = lastName;
this.address = address;
this.phoneNumber = phoneNumber;
this.emailAddress = emailAddress;
}
public void setContactId(String input){
this.contactId = input;
}
public String getContactId(){
return contactId;
}
public void setFirstName(String input){
this.firstName = input;
}
public String getFirstName(){
return firstName;
}
public void setLastName(String input){
this.lastName = input;
}
public String getLastName(){
return lastName;
}
public void setAddress(String input){
this.address = input;
}
public String getAddress(){
return address;
}
public void setPhoneNumber(String input){
this.phoneNumber = input;
}
public String getPhoneNumber(){
return phoneNumber;
}
public void setEmailAddress(String input){
this.emailAddress = input;
}
public String getEmailAddress(){
return emailAddress;
}
void displayContacts(){
System.out.println("Contact ID:" + contactId + " First Name:" + firstName + " Last Name:" + lastName);
System.out.println("Address:" + address);
System.out.println("Phone Number:" + phoneNumber);
System.out.println("Email Address:" + emailAddress);
}
}
我的一個子類：其它相同，只是增加了幾個變量： 顯示聯繫人（）：無法確定如何處理它。
/* *要更改此許可證標題，請在項目屬性中選擇許可證標題。 *要更改此模板文件，請選擇工具|模板 *並在編輯器中打開模板。 */
package ooo1;
公共類PersonalContact擴展聯繫{
private String dateofBirth;
public PersonalContact(String contactId, String firstName, String lastName, String address, String phoneNumber, String emailAddress, String dateofBirth){
super(contactId, firstName, lastName, address, phoneNumber, emailAddress);
this.dateofBirth = dateofBirth;
}
public void setDateofBirth(String input){
this.dateofBirth=input;
}
public String getDateofBirth(){
return this.dateofBirth;
}
@Override
public void displayContacts(){
System.out.print("Personal Contacts: ");
System.out.println("Contact ID:" + contactId + " First Name:" + firstName + " Last Name:" + lastName);
System.out.println("Address:" + address);
System.out.println("Phone Number:" + phoneNumber);
System.out.println("Email Address:" + emailAddress);
System.out.println("Birthday:" + dateofBirth);
}
}
我認爲這是正確的，聯繫人只代表1個聯繫人。如果你想分開列表，那麼你可以看看創建一個包含一組聯繫人的AddressBook類。 –
如果我以這種方式對我如何打印聯繫人列表感到困惑。我需要他們分開個人和商業，並需要能夠通過contactID呼叫某個聯繫人。如果我能夠獲得打印功能，我會稱這爲第一次嘗試。如果創建了一個地址簿類，那將如何工作。 – user3196742