MySQL查詢在JSON代碼不工作

Question

我必須返回折扣券一個JSON Ajax代碼...代碼工作正常，但只要可能，我運行AJAX頁面查詢。該響應停止工作

JavaScript代碼：

<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script> 
$(document).ready(function() { 


    $("#submit_btn").click(function() { 
     //get input field values 
     var user_name = $('input[name=discountBox]').val(); 

     //simple validation at client's end 
     //we simply change border color to red if empty field using .css() 
     var proceed = true; 
     if(user_name==""){ 
      $('input[name=discountBox]').css('border-color','red'); 
      proceed = false; 
     } 

     //everything looks good! proceed... 
     if(proceed) { 
     //data to be sent to server 
      post_data = {'discountBox':user_name}; 

      //Ajax post data to server 
      $.post('checking-discount.php', post_data, function(response){ 

       //load json data from server and output message  
       if(response.type == 'error') 
       { 
        output = '<div class="error">'+response.text+'</div>'; 
       }else{ 
        output = '<div class="success_2">'+response.text+'</div>'; 

        //reset values in all input fields 
        $('#contact_form input').val(''); 
       } 

       $("#result").hide().html(output).slideDown(); 
      }, 'json'); 
     } 
    }); 


    //reset previously set border colors and hide all message on .keyup() 
    $("#contact_form input, #contact_form textarea").keyup(function() { 
     $("#contact_form input, #contact_form textarea").css('border-color',''); 
     $("#result").slideUp(); 
    }); 
}); 

Ajax頁面： 檢查，discount.php

if($_POST){ 
    include_once("db.php"); 

    //check if its an ajax request, exit if not 
    if(!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') { 

     //exit script outputting json data 
     $output = json_encode(
     array(
      'type'=>'error', 
      'text' => 'Request must come from Ajax' 
     )); 

     die($output); 
    } 

    //check $_POST vars are set, exit if any missing 
    if(!isset($_POST["discountBox"])) 
    { 
     $output = json_encode(array('type'=>'error', 'text' => 'Please enter the code!!')); 
     die($output); 
    } 

    //Sanitize input data using PHP filter_var(). 
    $user_Name = filter_var($_POST["discountBox"], FILTER_SANITIZE_STRING); 

    //additional php validation 
    if(strlen($user_Name)<4) // If length is less than 4 it will throw an HTTP error. 
    { 
     $output = json_encode(array('type'=>'error', 'text' => 'Discount Code is too short or empty!')); 
     die($output); 
    } 

    $coupQuery = "select * tableName where field = '$user_Name'"; 
    $result = mysql_query($coupQuery) or die('MySql Error' . mysql_error()); 
    $row = mysql_fetch_array($result); 

    //print_r($couRow); 

    $discountAmt = 10; 
    //proceed with PHP email. 

    //if(count($couRow)>0){ 
     $output = json_encode(array('type'=>'message', 'text' => $coupQuery)); 
     die($output); 
    //}else{ 
     //$output = json_encode(array('type'=>'error', 'text' => 'Could not find the Discount Code! Please check your code.')); 
     //die($output); 
    //} 
} 

每當我刪除$結果和$行代碼其查詢工作正常，但它不允許提取的行..

請讓我知道我錯在哪裏..？

Answer 1

我在PHP解決一些編碼糾正問題...以下是代碼校正

if(!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') { 
    //exit script outputting json data 
    $output = json_encode(
    array(
     'type'=>'error', 
     'text' => 'Request must come from Ajax' 
    )); 
    die($output); 
} 

//check $_POST vars are set, exit if any missing 
if(!isset($_POST["discountBox"])) 
{ 
    $output = json_encode(array('type'=>'error', 'text' => 'Please enter the code!!')); 
    die($output); 
} 

//Sanitize input data using PHP filter_var(). 
$user_Name = filter_var($_POST["discountBox"], FILTER_SANITIZE_STRING); 

//additional php validation 
if(strlen($user_Name)<4) // If length is less than 4 it will throw an HTTP error. 
{ 
    $output = json_encode(array('type'=>'error', 'text' => 'Discount Code is too short or empty!')); 
    die($output); 
} 
$total = $_GET["totalAmt"]; 
$date = date('Y-m-d'); 
$coupQuery = "select * from ghasitaram_coupon where gha_coupon_code = '$user_Name' AND gha_coupon_status='1' AND '$date' between gha_coupon_startDate and gha_coupon_endDate AND $total between gha_coupon_startRange and gha_coupon_endRange"; 
$result = mysql_query($coupQuery) or die('MySql Error' . mysql_error()); 
$row = mysql_fetch_array($result); 
$num_rows = mysql_num_rows($result); 
$disPercent = $obj->stringEncryption(str_replace("%","",$row['gha_coupon_discount'])); 
//proceed with PHP email. 

if($num_rows>0){  
    $output = json_encode(array('type'=>'message', 'text' => 'Applying code for Discount', 'code' => $disPercent)); 
    die($output); 
}else{ 
    $output = json_encode(array('type'=>'error', 'text' => 'Could not find the Discount Code! Please check your code.')); 
    die($output); 
} 

Answer 2

編輯這一行

$coupQuery = "select * tableName where field = '$user_Name'"; 

到（插入from前tableName）

$coupQuery = "select * from tableName where field = '$user_Name'";