推文的日期和時間？

我想獲取特定推文的標準格式的日期和時間。這是下面的代碼，我現在用： -推文的日期和時間？

import tweepy 
import time 
import datetime 
from tweepy import OAuthHandler 
from tweepy import Stream 
from tweepy.streaming import StreamListener 
import string 
from nltk.corpus import stopwords 
from nltk.tokenize import TweetTokenizer 

consumer_key = '' #your consumer key 
consumer_secret = '' # your consumer secret 
access_token = '' # your access token 
access_secret = '' # your access secret 
auth = OAuthHandler(consumer_key, consumer_secret) 
auth.set_access_token(access_token, access_secret) 

api = tweepy.API(auth) 


class MyListener(StreamListener): 


    def on_data(self, data): 
     try: 
      tweet=data.split('","text":"')[1].split('","source":"')[0] 
      saveThis=str(time.time())+'::'+tweet 
      with open('twitDB.csv', 'a') as f: 
       f.write(saveThis) 
       f.write('\n') 
       f.close() 
       return True 
     except BaseException as e: 
      print(str(e)) 
     return True 

    def on_error(self, status): 
     print(status) 
     return True 


twitter_stream = Stream(auth, MyListener()) 
twitter_stream.filter(track=['cars'], languages=['en'])

這是我從這個越來越： -

1495596971.6034188::automotive auto ebc greenstuff 6000 series supreme truck 
and suv brake pads dp61603 https:\/\/t.co\/jpylzjyd5o cars\u2026 
https:\/\/t.co\/gfsbz6pkj7""display_text_range:[0140]source:""\u003ca 
href=\""https:\/\/dlvrit.com\/\"" 
rel=\""nofollow\""\u003edlvr.it\u003c\/a\u003e""" 
"1495596972.330948::new free stock photo of city cars road 
https:\/\/t.co\/qbkgvkfgpp""display_text_range:[0" 
"1495596972.775966::ebay: 1974 volkswagen beetle - classic 1952 custom 
conversion extremely rare 1974 vw beetle\u2026\u2026 
https:\/\/t.co\/wdsnf2pmo7""display_text_range:[0140]source:""\u003ca 
href=\""https:\/\/dlvrit.com\/\"" 
rel=\""nofollow\""\u003edlvr.it\u003c\/a\u003e"""

我想要的日期和時間標準的格式，而不是「1495596971.6034188」。你知道我該怎麼做？

來源

2017-05-25 Vic13

你也有「」。使用推文的創建日期的選項，它被嵌入在JSON中作爲'「created_at」：「Wed Aug 27 13:08:45 +0000 2008」'。 – Jonas

下面是基本的例子Unix時間戳轉換爲可讀的日期：

import datetime 
print(
    datetime.datetime.fromtimestamp(
     int("1495596971") 
    ).strftime('%Y-%m-%d %H:%M:%S') 
) 
>>2017-05-24 03:36:11

需要「1495596971.6034188" 通過分裂（）」，並使用所述第一索引[0]

來源

2017-05-25 04:55:20 mtkilic

感謝您的幫助:) – Vic13

@ Vic13不客氣謝謝你接受答案:) – mtkilic

推文的日期和時間？

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