PHP Help：if（$ row ['cDeviceRegistrationId']> 0）{$ a = 1;} echo $ a;

Question

如果數據庫中的cDeviceRegistrationId列有值，我試圖打印出「1」。下面是代碼：

$結果是一個SQL查詢

while($row = mysql_fetch_assoc($result)) 
    { 
if ($row['cDeviceRegistrationId'] > 0) { 
$a = 1; 
} 

echo "<tr class='forum'>"; 
echo "<td class='forum'>" . $row['intUserID'] . "</td>"; 
echo "<td class='forum'>" . $row['cUsername'] . "</td>"; 
echo "<td class='forum'>" . $row['cEmail'] . "</td>"; 
echo "<td class='forum'>$a</td>"; 
echo "<td class='forum'>" . $row['uCreateDate'] . "</td>"; 
echo "</tr>"; 
} 

Answer 1

的$a的值，如果不符合條件，這意味着其他迭代可以得到1值錯誤不會被覆蓋。下面是一個修復（更換您的if語句）：

$a = ($row['cDeviceRegistrationId'] > 0) ? 1 : ''; 

Answer 2

如何：

if(!is_null($row['cDeviceRegistrationId'])){ 
    $a = 1; 
}