回顯查詢結果迷戀

-2

$sql = "SELECT date, email, journal, section FROM selection_loggedin WHERE email = '$email' and date in (SELECT max(date) FROM (SELECT date, email FROM selection_loggedin WHERE email = '$email') as x)"; 
$result = $dbc->query($sql); 

if ($result->num_rows > 0) { 

while($row = $result->fetch_assoc()) { 
    $journal = row['journal']; 
    $section = row['section']; 
    print_r($row); 
    //echo "'$journal'"."'$section'"; 
    echo "<br>".row['email']."<br>"; 
    echo row['date']."<br>";

而且我得到這個：

Array ( 
     [date] => 2017-05-07 12:45:45 
     [email] => [email protected] 
     [journal] => Wall Street Journal 
     [section] => Economy 
)

爲什麼它不打印正確的東西（'華爾街街頭日報「和」經濟「）？

來源

2017-05-07 ben

因爲你打印整個'$ row'，並且你在'$ sql'查詢中選擇了這些列。你是否期望它做別的事情？ – rickdenhaan

print_r默認回顯。評論線。 –

別管我以前的評論，我現在明白了這個問題。你正在嘗試從'row'讀取列，你應該從'$ row'讀取數據（注意$''） – rickdenhaan

$sql = "SELECT date, email, journal, section FROM selection_loggedin WHERE email = '$email' and date in (SELECT max(date) FROM (SELECT date, email FROM selection_loggedin WHERE email = '$email') as x)"; 
$result = $dbc->query($sql); 

if ($result->num_rows > 0) { 

while($row = $result->fetch_assoc()) { 
    $journal = $row['journal']; 
    $section = $row['section']; 
    print_r($row); 
    //echo "'$journal'"."'$section'"; 
    echo "<br>".$row['email']."<br>"; 
    echo $row['date']."<br>";

來源

2017-05-07 12:08:15 Osama

回顯查詢結果迷戀

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