我只是想重新指定一個行(來自同一個表)作爲新行1替換自動增加MySQL的行與另一
該表有列「版本」作爲AI
其他三列(名,arrayV,筆記)
CURRENT失敗的嘗試(只是SQL語法,使用固定的值,而不是變量)
UPDATE `variables` AS v1, `variables` AS v2 SET v1.`name` = v2.`name`, v1.`arrayV` = v2.`arrayV`, v1.`notes` = v2.`notes` WHERE v1.`version`=1,v2.`version`= 5;
PREVIOUS失敗嘗試
$newAI1 = $_POST["newSet"];//variable is an integer equal to another row ('version') in table
echo "New set of is ".$newAI1."<br/>";
$sqlMove = "INSERT INTO `variables` (`name`,`arrayV`,`notes`) WHERE `version` = '1' (SELECT `name`,`arrayV`,`notes` FROM `variables` WHERE `version` = '".$newAI1."')";
我在哪裏出錯了?
在你的插入查詢表名值'variables'是用單引號覆蓋?它必須蓋上'sign – Naeem
請定義什麼是版本?嘗試類似 INSERT INTO USER(user_name)(SELECT user_name FROM USER WHERE id ='13') – user12
@naeem,''(反引號)或''(單引號),要用哪個? – Gamemorize