使用EXCEPT或INTERSECT僅顯示不匹配的行

Question

假設我有2個結果集（2個查詢）。

FIELDNAME VALUE 
field1  20.00 
field2  13.00 
field3  4.00 

FIELDNAME VALUE 
field1  20.00 
field2  14.00 
field3  6.00 

我知道query1 EXCEPT query2應該給

FIELDNAME VALUE 
field2  13.00 
field3  4.00 

但我真正想要的是表現出任何情況下，是有區別的，從查詢的兩面：

FIELDNAME VALUE 
field2  13.00 
field3  4.00 
field2  14.00 
field3  6.00 

是那可能嗎？我想我可以做一個SELECT UNION到一個臨時表中。然後刪除不存在具有不同值的NOT EXISTS字段名的行。更簡單嗎？

看起來我可以將INTERSECT，UNION和EXCEPT結合起來，但是沒有太多運氣的概念。

Answer 1

我想你應該能夠得到你需要使用EXCEPT兩次，並使用對結果UNION ALL：

-- records from the table1 that are not in table2 
(SELECT * FROM table1 
EXCEPT 
SELECT * FROM table2) 

UNION ALL 

-- records from the table2 that are not in table1 
(SELECT * FROM table2 
EXCEPT 
SELECT * FROM table1) 

另一種方法是使用UNION獲得所有表的組合，然後使用EXCEPT消除所有相交的記錄：

-- Union of both tables 
(SELECT * FROM table1 
UNION ALL 
SELECT * FROM table2) 

EXCEPT -- Exclude the records ... 

-- ... that are in both tables 
(SELECT * FROM table1 
INTERSECT 
SELECT * FROM table2) 

Answer 2

這就像XOR操作：

DECLARE @Table1 TABLE(Name nvarchar(20), Value decimal) 
DECLARE @Table2 TABLE(Name nvarchar(20), Value decimal) 

INSERT INTO @Table1 
VALUES 
(N'field1', 20.00), 
(N'field2', 13.00), 
(N'field3', 4.00) 


INSERT INTO @Table2 
VALUES 
(N'field1', 20.00), 
(N'field2', 14.00), 
(N'field3', 6.00) 


SELECT * 
FROM 
(
    SELECT * 
    FROM @Table1 AS t 
    EXCEPT (SELECT * FROM @Table2 AS t) 
) AS a 
UNION 
SELECT * 
FROM 
(
    SELECT * 
    FROM @Table2 AS t 
    EXCEPT (SELECT * FROM @Table1 AS t) 
) AS b 

Answer 3

根據你的文章，你已經嘗試了INTERSECT，UNION和EXCEPT組合，但沒有得到輸出。

嘗試使用（INTERSECT，UNION和EXCEPT）來獲取它。

DECLARE @Table1 TABLE(Name nvarchar(20), Value decimal(18,2)) 
DECLARE @Table2 TABLE(Name nvarchar(20), Value decimal(18,2)) 

INSERT INTO @Table1 
VALUES 
(N'field1', 20.00), 
(N'field2', 13.00), 
(N'field3', 4.00) 


INSERT INTO @Table2 
VALUES 
(N'field1', 20.00), 
(N'field2', 14.00), 
(N'field3', 6.00) 

select *From @Table1 
union 
select *From @Table2 
except 
select *From @Table1 
intersect 
select *From @Table2