Python：只需要字典中的特定值;正常化節點密鑰對

Question

因此，現在我有一個字典dataDict，它具有值爲'node-key'的鍵，其中節點是特定的csv文件頭，鍵是可能存在或不存在於每個文件中的字段。我有一個normalDict['Time']需要從dataDict[node-'Time']所有時間，並把他們整理。我想爲dataDict中的每個'node-key'條目製作一個規範化字典。於是我通過normalDict['Time']值迭代，如果i爲dataDict[nodeTime]，我想在同一位置添加dataDict[nodeKey]價值爲dataDict[nodeTime]到normalDict[nodeKey]，而如果normalDict['Time']值不在dataDict[nodeTime]，我想追加一個'nan'到normalDict[nodeKey]。

（我的腳本目前的圖dataDict [nodeKey] vs dataDict [nodeTime]，我想規範化時間以包括所有節點的時間在一個軸上，並添加'nan的dataDict [nodeKey]到值沒有發生）

編輯：澄清： 所以可以說我有

所以說

dataDict['1-Time'] = ['12:00','1:00','2:00'] 
dataDict['2-Time'] = ['12:30','1:30','2:30','3:30'] 

我也有一個具有相同數目的項鍵的值，列在兩次這樣：

dataDict['1-lattitude']=['0','1','2'] 
dataDict['2-lattitude']= ['1','2','3','3'] 

而且

normalDict['Time'] = ['12:00','12:30','1:00','1:30','2:00','2:30','3:30'] 

話，我想有

normalDict['1-lattitude'] = [ '0', 'nan', '1', 'nan', 2', 'nan', 'nan']` 

和

normalDict['2-lattitude'] = ['nan', '1', 'nan', '2', 'nan', '3', '3'] 

因此，在normalDict每個按鍵都有價值爲等量在normalDict['Time']

這裏是我的方法，我已經評論了我的頭腦中有意義的特定行，以便如何訪問特定鍵的單個項目，但是我知道由於解包錯誤導致它不正確。任何幫助將不勝感激，因爲我可能會遇到與後面的腳本這個問題。

def normalizeDataByField(self, fileName,keyNames): 

     #this normalizes time how I want 
     setTimes = set() 
     listTimes = [] 
     tupleTime=[] 
     for i in range(len(fileName)): 
      node = self.deriveNodeName(fileName[i]) 
      nodeTime= '%s-Time' %(node) 
      for key in dataDict: 
       if 'Time' in key and node in key: 
        for i in dataDict[key]: 
         setTimes.add(i) 
      listTimes+=setTimes 
      listTimes.sort() 
      normalDict['Time'] = listTimes 


     for a in range(len(fileName)): 
      node = node = self.deriveNodeName(fileName[a]) 
      nodeTime='%s-Time' %(node) 
      for key in keyNames: 
       nodeKey= '%s-%s' %(node,key) 

       for i,j in normalDict['Time'],dataDict[nodeKey]: #this is my flaw in logic as I get ValueError: too many values to unpack 

        print "looking for %s in dataDict[nodeTime]" %(i) 
        if i in dataDict[nodeTime]: 
         print "%s found in dataDict[%s]" %(i,nodeTime) 
         normalDict[nodeKey].append(j) 
        else: 
         print "%s not found in dataDict[%s]. Appending 'nan'" %(i,nodeTime) 
         normalDict[nodeKey].append('nan') 

Answer 1

所以我相信我能回答我自己的問題，但它有點混亂。我決定將每個dataDict[nodeKey]存儲在列表dataList中，並根據其列表索引j將值附加到normalDict[nodeKey]。我也在創建normalDict['Time']的for循環中發現錯誤。

def normalizeDataByField(self, fileName,keyNames): 
    setTimes = set() 
    listTimes = [] 
    tupleTime=[] 
    for i in range(len(fileName)): 
     node = self.deriveNodeName(fileName[i]) 
     nodeTime= '%s-Time' %(node) 

     for key in dataDict: 
      if nodeTime in key: 
       for i in dataDict[key]: 
        setTimes.add(i) 
    listTimes+=setTimes 
    listTimes.sort() 
    normalDict['Time'] = listTimes 


    for a in range(len(fileName)): 
     node = node = self.deriveNodeName(fileName[a]) 
     nodeTime='%s-Time' %(node) 
     for key in keyNames: 
      if 'Time' not in key: 
       nodeKey= '%s-%s' %(node,key) 
       dataList = dataDict[nodeKey] 
       j=0 
       for i in normalDict['Time']: 
        print "looking for %s in dataDict[nodeTime]" %(i) 
        if i in dataDict[nodeTime]: 
         print "%s found in dataDict[%s]. Appending value." %(i,nodeTime) 
         try: 
          normalDict[nodeKey].append(dataList[j]) 
          j+=1 
          print "j = ",j 
         except: 
          print "Index out of range. j = ", j 
        else: 
         print "%s not found in dataDict[%s]. Appending 'nan'" %(i,nodeTime) 
         normalDict[nodeKey].append('nan') 
    for key in normalDict: 
     print "len(normalDict[%s] = %d" %(key, len(normalDict[key])) 

這最後一個for循環顯示normalDict中的所有鍵具有相同的長度。 也許這不是最漂亮的解決辦法，但我還是能夠創建與我所需要的值，並把「南」值的字典在必要時與對應normalDict['Time']

Answer 2

time_key='1-Time' 
lattitude_key='1-lattitude' 

def normalize(normalDict, dataDict, lattitude_key, time_key): 
    normalDict[lattitude_key]=['nan' for _ in range(len(normalDict['Time']))] 
    for i, e in enumerate(dataDict[time_key]): 
     normalDict[lattitude_key][normalDict['Time'].index(e)]=dataDict[lattitude_key][i]