爲什麼php代碼不會迴應任何內容？

Question

<?php 
$svg_file = file_get_contents("fonts/font.svg"); 
$font = new DOMDocument(); 
$font->load($svg_file); 
$glyphs = $font->getElementsByTagName('glyph'); 

foreach($glyphs as $g) { 
    echo $g->getAttribute('glyph-name'); 
} 
?> 

我在哪裏錯了上面的代碼？它不會回任何東西，試圖在本地主機上

Answer 1

試試這個：

$font = new DOMDocument(); 
$font->load("fonts/font.svg"); 
$glyphs = $font->getElementsByTagName('glyph'); 

foreach($glyphs as $g) { 
    echo $g->getAttribute('glyph-name'); 
} 

UPDATE：

$font = new DOMDocument(); 
$font->load("fonts/font.svg"); 
$glyphs = $font->getElementsByTagName('glyph'); 
$arr_names = array(); 
foreach($glyphs as $g) { 
    $arr_names[] = $g->nodeValue; 
} 
$sort($arr_names); 
foreach($arr_names as $name){ 
    echo $name; 
} 

UPDATE：

$font = new DOMDocument(); 
$font->load("fonts/font.svg"); 
$glyphs = $font->getElementsByTagName('glyph'); 
$arr_names = array(); 
foreach($glyphs as $g) { 
    $arr_names[] = $g->nodeValue; 
} 
sort($arr_names); 
foreach($arr_names as $name){ 
    echo $name; 
}