將nextLIne（）與nextInt（）一起使用

Question

我是java的初學者。雖然做這個簡單的程序（該程序很長，請不要介意）我發現：

這是行不通的。

import java.util.*; 
class store 
{ 
    store() 
    { 
     System.out.println("RESLUTS OF STUDENTS"); 
     System.out.println(); 
    } 
    void stu1 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu2 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu3 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu4 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu5 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
} 
class stu 
{ 
    public static void main(String[] args) { 
     Scanner v = new Scanner (System.in); 
     System.out.println("Enter the name of first student"); 
     String p = v.nextLine(); 
     System.out.println("Enter the marks for first student"); 
     int q = v.nextInt(); 
     System.out.println("Enter the name of second student"); 
     String r = v.nextLine(); 
     System.out.println("Enter the marks for second student"); 
     int s = v.nextInt(); 
     System.out.println("Enter the name of third student"); 
     String t = v.nextLine(); 
     System.out.println("Enter the marks for third student"); 
     int u = v.nextInt(); 
     System.out.println("Enter the name of fourth student"); 
     String w = v.nextLine(); 
     System.out.println("Enter the marks for fourth student"); 
     int x = v.nextInt(); 
     System.out.println("Enter the name of fifth student"); 
     String y = v.nextLine(); 
     System.out.println("Enter the marks for fifth student"); 
     int z = v.nextInt(); 
     store st = new store(); 
     st.stu1(p,q); 
     st.stu2(r,s); 
     st.stu3(t,u); 
     st.stu4(w,x); 
     st.stu5(y,z); 
    } 
} 

但是這樣做。nextLine（）和nextInt（）與print語句分開。

import java.util.*; 
class store 
{ 
    store() 
    { 
     System.out.println("RESLUTS OF STUDENTS"); 
     System.out.println(); 
    } 
    void stu1 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu2 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu3 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu4 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
    void stu5 (String name,int marks) 
    { 
     System.out.println("The name of student is : "+ name+" and he got :"+marks+"marks"); 
    } 
} 
class stu 
{ 
    public static void main(String[] args) { 
     Scanner v = new Scanner (System.in); 
     System.out.println("Enter the name of first student"); 
     String p = v.nextLine(); 
     System.out.println("Enter the name of second student"); 
     String r = v.nextLine(); 
     System.out.println("Enter the name of third student"); 
     String t = v.nextLine(); 
     System.out.println("Enter the name of fourth student"); 
     String w = v.nextLine(); 
     System.out.println("Enter the name of fifth student"); 
     String y = v.nextLine(); 
     System.out.println("Enter the marks for first student"); 
     int q = v.nextInt(); 
     System.out.println("Enter the marks for second student"); 
     int s = v.nextInt(); 
     System.out.println("Enter the marks for third student"); 
     int u = v.nextInt(); 
     System.out.println("Enter the marks for fourth student"); 
     int x = v.nextInt(); 
     System.out.println("Enter the marks for fifth student"); 
     int z = v.nextInt(); 
     store st = new store(); 
     st.stu1(p,q); 
     st.stu2(r,s); 
     st.stu3(t,u); 
     st.stu4(w,x); 
     st.stu5(y,z); 
    } 
} 

這是爲什麼？它不是基本相同嗎？還是有其他方法可以做到這一點？

Answer 1

那是因爲掃描儀＃nextInt方法不會消耗你輸入的最後一個換行符，因此該換行符在下次調用消耗掃描器＃nextLine

你的問題已經回答這裏：Scanner is skipping nextLine() after using next(), nextInt() or other nextFoo() methods