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我使用Ruby Roo來閱讀下面的xls文件。如何在Ruby中爲每個ID創建哈希值
現在我想爲每個studentid這樣做散列。
132 = { "Design" => 6, "English" => 5, "Humanities" => 5, .... }
134 = { "Design" => 7, "English" => 6, "Humanities" => 6, .... }
...
...
以下是我所做的。它輸出的東西,但我需要建立創建哈希。
require_relative './subcorrelation/version'
require 'linefit'
require 'roo'
myfile='../data/msdataparts.xls'
workbook = Roo::Excel.new(myfile)
workbook.default_sheet = workbook.sheets.first
# Create a hash of the headers so we can access columns by name (assuming row
# 1 contains the column headings). This will also grab any data in hidden
# columns.
headers = Hash.new
workbook.row(1).each_with_index {|header,i|
headers[header] = i
}
# Iterate over the rows using the `first_row` and `last_row` methods. Skip
# the header row in the range.
((workbook.first_row + 1)..workbook.last_row).each do |row|
# Get the column data using the column heading.
studentid = workbook.row(row)
puts "{#studentid}"
end
我很欣賞任何輸入。提前致謝。
更新:上述線的輸出。
[132.0, "Design", 6.0, "MYC665", "S2", 7.0]
[132.0, "English", 5.0, "MYC600", "S2", 7.0]
[132.0, "Humanities", 5.0, "MYC610", "S2", 7.0]
[132.0, "Languages", 6.0, "MYJ660", "S2", 7.0]
[132.0, "Math", 6.0, "MYC620", "S2", 7.0]
[132.0, "Music", 7.0, "MYC664", "S2", 7.0]
[132.0, "PE", 6.0, "MYC650", "S2", 7.0]
[132.0, "Science", 6.0, "MYC630", "S2", 7.0]
[132.0, "Theatre", 6.0, "MYC661", "S2", 7.0]
[134.0, "Design", 7.0, "MYC665", "S2", 7.0]
[134.0, "English", 6.0, "MYC600", "S2", 7.0]
[134.0, "Humanities", 6.0, "MYC610", "S2", 7.0]
[134.0, "Languages", 6.0, "MYS610", "S2", 7.0]
...
...
謝謝。我剛剛更新了我的帖子。 – shin
更新我的回答 – bjhaid
錯誤:...'塊在