如何用xPath選擇多個元素？

Question

我正在使用defiantjs來選擇對象中的元素。這是我的對象：

{ 
"name": "Retail Sales", 
"weight": 10, 
"length": 6, 
"type": "retailSales", 
"rows": [ 
    { 
    "dealerEvaluationHistoryID": 0, 
    "performanceDealerMappingDetailID": 14, 
    "month": 1, 
    "plan": 0, 
    "actual": 0, 
    "weight": 0, 
    "pelanggaranWilayah": 0 
    }, 
    { 
    "dealerEvaluationHistoryID": 0, 
    "performanceDealerMappingDetailID": 14, 
    "month": 2, 
    "plan": 0, 
    "actual": 0, 
    "weight": 0, 
    "pelanggaranWilayah": 0 
    }, 
    { 
    "dealerEvaluationHistoryID": 0, 
    "performanceDealerMappingDetailID": 14, 
    "month": 3, 
    "plan": 0, 
    "actual": 0, 
    "weight": 0, 
    "pelanggaranWilayah": 0 
    } 
] 
} 

如何在行[]中的每個對象中選擇所有月份，計劃，實際和重量？ 想我喜歡這樣的輸出：

[[1,0,0,0],[2,0,0,0],[3,0,0,0]] 

我可以做//rows/month和//rows/plan但不知道如何執行這兩種。

Answer 1

您可以使用map方法，該方法對陣列中的每個項目應用回調函數函數。

瞭解更多關於map方法。

let obj={ 
 
    "name": "Retail Sales", 
 
    "weight": 10, 
 
    "length": 6, 
 
    "type": "retailSales", 
 
    "rows": [ 
 
     { 
 
     "dealerEvaluationHistoryID": 0, 
 
     "performanceDealerMappingDetailID": 14, 
 
     "month": 1, 
 
     "plan": 0, 
 
     "actual": 0, 
 
     "weight": 0, 
 
     "pelanggaranWilayah": 0 
 
     }, 
 
     { 
 
     "dealerEvaluationHistoryID": 0, 
 
     "performanceDealerMappingDetailID": 14, 
 
     "month": 2, 
 
     "plan": 0, 
 
     "actual": 0, 
 
     "weight": 0, 
 
     "pelanggaranWilayah": 0 
 
     }, 
 
     { 
 
     "dealerEvaluationHistoryID": 0, 
 
     "performanceDealerMappingDetailID": 14, 
 
     "month": 3, 
 
     "plan": 0, 
 
     "actual": 0, 
 
     "weight": 0, 
 
     "pelanggaranWilayah": 0 
 
     } 
 
    ] 
 
} 
 
let array=obj.rows.map(function(row){ 
 
    return [row.month,row.plan,row.actual,row.weight]; 
 
}); 
 
console.log(JSON.stringify(array));