這裏有什麼不對? 我已經寫了下面的代碼來更新url參數「緯度」和「lng」使用MySQL數據庫列degree_n,minute_n等,但沒有發生。我要的是每次運行此腳本時,該URL應該使用MySQL數據庫的現值無法修改url參數
<?php
$servername = "localhost";
$username = "id1116502_track_data";
$password = "***";
$dbname = "****";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$url = "http://ws.geonames.org/countryCodeJSON?lat=<?php
$servername = "localhost";
$username = "id1116502_track_data";
$password = "***";
$dbname = "****";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT degree_n, minute_n FROM coordinates ORDER BY id DESC limit 1 ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
print " " .$row["degree_n"]. "." .$row["minute_n"]. " ";
}
} else {
echo "0 results";
}
$conn->close();
?>&lng=<?php
$servername = "localhost";
$username = "id1116502_track_data";
$password = "****";
$dbname = "****";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT degree_e, minute_e FROM coordinates ORDER BY id DESC limit 1 ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
print " " .$row["degree_e"]. "." .$row["minute_e"]. " ";
}
} else {
echo "0 results";
}
$conn->close();
?>&username=****8";
echo "$url";
?>
你寫什麼這一行 - >'$ url =「http://ws.geonames.org/countryCodeJSON?lat= <?php'爲什麼php標籤有沒有正確關閉 – webpic
那麼你應該修改$ url變量,難道你不知道這樣想嗎?你不需要關閉連接,然後重新連接,以確保evefy sql語句。 – Shadow
我沒有打開和關閉<?php太...但它不工作..這似乎是我不能修改$ url ...沒有任何工作 –