我想解析一些JSON。這是代碼。 frc-manual.usfirst.org/a/GetAllItems/ManualID=3我一直在嘗試幾個小時才能正常工作,但我在網上看到的每個示例都使用getJSONObject(int),但我只能使用getJSONObject(String)。這是不可能的。我可以忽略一些東西嗎使用getJSONObject(int)
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.StringWriter;
import java.io.UnsupportedEncodingException;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.SortedMap;
import java.util.TreeMap;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import org.xmlpull.v1.XmlPullParser;
import org.xmlpull.v1.XmlPullParserFactory;
import android.annotation.SuppressLint;
public class JSON {
private String html = "html";
private String version = "version";
private String pageString = null;
private String urlString = "http://frc-manual.usfirst.org/a/GetAllItems/ManualID=3";
public volatile boolean parsingComplete = true;
public JSON(String page){
this.pageString = page;
}
public String getHTML(){
return html;
}
public String getVersion(){
return version;
}
@SuppressLint("NewApi")
public void readAndParseJSON(String in) {
try {
JSONObject reader = new JSONObject(in);
JSONObject head = reader.getJSONObject("data").getJSONObject("SubChapter").getJSONObject("3").getJSONObject("children").getJSONObject(pageString);
if(head != null){
html = head.getString("item_content_text");
html = html + head.length();
for(int i = 0; i < head.length();i++){
JSONObject children = head.getJSONObject(i);
if(children != null){
html = html + children.getString("item_content_text");
}
}
}
//html = html + listFromJsonSorted(head.getJSONObject("children"));
JSONObject main = reader.getJSONObject("data");
version = main.getString("LatestManualUpdate");
parsingComplete = false;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public void fetchJSON(){
Thread thread = new Thread(new Runnable(){
@Override
public void run() {
try {
URL url = new URL(urlString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
// Starts the query
conn.connect();
InputStream stream = conn.getInputStream();
String data = convertStreamToString(stream);
readAndParseJSON(data);
stream.close();
} catch (Exception e) {
e.printStackTrace();
}
}
});
thread.start();
}
static String convertStreamToString(java.io.InputStream is) {
java.util.Scanner s = new java.util.Scanner(is).useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
}
是的,但我也需要在兒童節點 – AquaMorph
,但你已經得到了你的代碼中的子節點,我沒有看到更多的孩子在你發佈的JSON作爲例子 –
我想我明白你的問題,你可以有一個對象,有一個孩子,也許有一個孩子,等等。所以你可以做到這一點。 JSONObject children = head.getJSONObject(「children」);如果(children!= null)concat –