我想對我的表運行鍼對給定值的查詢,並根據是否找到一行返回Maybe a
。Opaleye按字符串查詢到Maybe
我有這個域名:
data User' a b c d e f = User { usrId :: a,
usrApproved :: b,
usrIden :: c,
usrImgUrl :: d,
usrTitle :: e,
usrUrl :: f
}
type User = User' Int Bool String String String String
$(makeAdaptorAndInstance "pUser" ''User')
type UserColumn = User' (Column PGInt4) (Column PGBool) (Column PGText) (Column PGText) (Column PGText) (Column PGText)
和表下面的定義和查詢:
userTable :: Table UserColumn UserColumn
userTable = Table "user" (pUser User { usrId = required "id",
usrApproved = required "approved",
usrIden = required "identifier",
usrImgUrl = required "img_url",
usrTitle = required "title",
usrUrl = required "url"
})
userQuery :: Query UserColumn
userQuery = queryTable userTable
正如前面所暗示的那樣,我想用「標識符」一欄進行查詢,所以我已經寫了這個查詢並且希望返回一個`IO(也許用戶)
userByIdenQuery :: (Column PGText) -> Query UserColumn
userByIdenQuery iden = proc() -> do
user <- userQuery -<()
restrict -< (adIden user) .=== iden
returnA -< user
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = do
usr <- runQuery c (userByIdenQuery $ pgString iden)
-- But this fails to compile
undefined -- just to minimise compilation errors
這個失敗無法編譯wi日:
No instance for (Default
Opaleye.Internal.RunQuery.QueryRunner UserColumn haskells0)
arising from a use of `runQuery'
The type variable `haskells0' is ambiguous
Note: there is a potential instance available:
instance (product-profunctors-0.7.1.0:Data.Profunctor.Product.Class.ProductProfunctor
p,
Default p a1_0 a1_1, Default p a2_0 a2_1, Default p a3_0 a3_1,
Default p a4_0 a4_1, Default p a5_0 a5_1, Default p a6_0 a6_1) =>
Default
p
(User' a1_0 a2_0 a3_0 a4_0 a5_0 a6_0)
(User' a1_1 a2_1 a3_1 a4_1 a5_1 a6_1)
-- Defined at src\DB.hs:33:3
In a stmt of a 'do' block:
usr <- runQuery c (userByIdenQuery $ pgString iden)
In the expression:
do { usr <- runQuery c (userByIdenQuery $ pgString iden);
undefined }
In an equation for `getUserByIden':
getUserByIden iden c
= do { usr <- runQuery c (userByIdenQuery $ pgString iden);
undefined }
如果我試圖實現功能:
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = do
(usrId, appr, idn, imUrl, tit, url) <- runQuery c (userByIdenQuery $ pgString iden)
return $ Just $ User usrId appr idn imUrl tit url
然後我提出這個編譯錯誤:
Couldn't match expected type `[haskells0]'
with actual type `(Int, Bool, String, String, String, String)'
In the pattern: (usrId, appr, idn, imUrl, tit, url)
In a stmt of a 'do' block:
(usrId, appr, idn, imUrl, tit, url) <- runQuery
c (userByIdenQuery $ pgString iden)
In the expression:
do { (usrId, appr, idn, imUrl, tit, url) <- runQuery
c (userByIdenQuery $ pgString iden);
return $ Just $ User usrId appr idn imUrl tit url }
I really have no idea where to go with this, other than using a library other than Opaleye.
'runQuery'有一個非常普遍的返回類型 - 給它一個類型簽名,或者返回一個類型簽名。 [docs](https://hackage.haskell.org/package/opaleye-0.5.0.0/docs/Opaleye-RunQuery.html)非常清楚地表明:「runQuery使用Default typeclass意味着編譯器將無法推斷強烈建議您在使用runQuery時提供完整類型的簽名。「 – user2407038
如何準確提供類型簽名?黑線鱈總是讓我困惑。 –
從某種意義上說,你已經給它一個類型簽名 - 'getUserByIden :: String - > PGS.Connection - > IO(也許用戶)' - 但是'usr'在主體中是未使用的,所以它不能與'User' 。如果你真的實現了這個功能,這可能就足夠了。與此同時,您可以通過多種方式編寫類型簽名:'(x :: X)< - a'或'x < - a :: IO X'或'_x < - a;讓x :: X; x = _x' – user2407038