將通配符整數放入字符串最簡單的方法是什麼？

Question

例如，如果我的代碼：

for row in self.reader: 
    if row: 
     if row[0] == "Stage * Disk Face": 
      """CODE TO EXECUTE""" 

然而，有沒有一種方法，使星號*任意號碼，這樣，如果找到字符串"Stage 1 Disk Face"或"Stage 2 Disk Face"或"Stage 3 Disk Face"等，代碼將執行？原因並不是每個階段號碼都會有磁盤面部特徵。我基本上需要找出是否至少有一個，任意數字。

Answer 1

這應該工作：

import re 

for row in self.reader: 
    if row: 
     if re.match('^Stage [0-9]+ Disk Face$', row[0]): 
      """CODE TO EXECUTE""" 

Answer 2

入住這

# coding=utf8 
# the above tag defines encoding for this document and is for Python 2.x compatibility 

import re 

regex = r"(Stage)[0-9](Disk Face)" 

test_str = "Stage 1 Disk Face" 

matches = re.search(regex, test_str) 

if matches: 
    print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group())) 

    for groupNum in range(0, len(matches.groups())): 
     groupNum = groupNum + 1 

     print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum))) 

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitutio 

Answer 3

import re 

#if row[0] == "Stage * Disk Face": 
if re.search(r'Stage \d Disk Face', row[0]): 
    pass 

Answer 4

這將是最簡單的只是使用正則表達式：

import re 

rows = [["Stage 1 Disk Face"], ["Stage 2 Disk Face"], ["Stage 3 Disk Face"]] 
pattern = re.compile("Stage .* Disk Face") 

for row in rows: 
    if row: 
     if pattern.match(row[0]): 
      print(row[0])