使用正則表達式從xml中獲取值

Question

我有以下xml。

string xmlstring= <z:row ows_Article_x0020_Tags='14;#cricket;#21;#Headlines;#19;#Videos' ows__ModerationStatus='0'  ows__Level='1' ows_Last_x0020_Modified='9;#2013-11-26 01:33:01' ows_ID='9' ows_UniqueId='9;#{FEA534D1-F63B-464D-97DE-  AC60798B72D6}' ows_owshiddenversion='9' ows_FSObjType='9;#0' ows_Created_x0020_Date='9;#2013-11-24 22:59:53' ows_ProgId='9;#' ows_FileLeafRef='9;#Pablo-Ferrero.aspx' ows_PermMask='0x7fffffffffffffff' ows_Modified='2013-11-26  01:33:01' ows_FileRef='9;#sites/Gaslines/NewsAndEvents/Pages/Pablo-Ferrero.aspx' ows_DocIcon='aspx'  ows_Editor='24;#Harshini P Hegde' />\r\n 
<z:row ows_Article_x0020_Tags='20;#Charity;#14;#cricket' ows__ModerationStatus='0' ows__Level='1' ows_Last_x0020_Modified='10;#2013-11-26 01:30:11' ows_ID='10' ows_UniqueId='10;#{C8D042AE-466F-44E8-940B- 0C9A64130923}' ows_owshiddenversion='8' ows_FSObjType='10;#0' ows_Created_x0020_Date='10;#2013-11-24 23:01:50' ows_ProgId='10;#' ows_FileLeafRef='10;#Debra-L-Reed.aspx' ows_PermMask='0x7fffffffffffffff' ows_Modified='2013-11- 26 01:3:10' ows_FileRef='10;#sites/Gaslines/NewsAndEvents/Pages/Debra-L-Reed.aspx' ows_DocIcon='aspx' ows_Editor='24;#Harshini P Hegde' />\r\n 
<z:row ows_Article_x0020_Tags='' ows__ModerationStatus='3' ows__Level='255' ows_Last_x0020_Modified='13;#2013-11-26  01:45:12' ows_ID='13' ows_UniqueId='13;#{81236BD1-AF3B-4D97-BA14-5492F8013251}' ows_owshiddenversion='5' ows_FSObjType='13;#0' ows_Created_x0020_Date='13;#2013-11-26 01:28:45' ows_ProgId='13;#' ows_FileLeafRef='13;#TestTagCloudPage.aspx' ows_PermMask='0x7fffffffffffffff' ows_Modified='2013-11-26 01:45:13' ows_CheckoutUser='24;#Harshini P Hegde' ows_FileRef='13;#sites/Gaslines/NewsAndEvents/Pages/TestTagCloudPage.aspx' ows_DocIcon='aspx' ows_Editor='24;#Harshini P Hegde' />\r\n</rs:data>\r\n</xml>" 

上面的XML也有stringxml之前以下

<xml xmlns:s='uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882'\r\n  xmlns:dt='uuid:C2F41010-65B3-11d1-A29F-00AA00C14882'\r\n  xmlns:rs='urn:schemas-microsoft-com:rowset'\r\n  xmlns:z='#RowsetSchema'>\r\n 
<s:Schema id='RowsetSchema'>\r\n 
<s:ElementType name='row' content='eltOnly' rs:CommandTimeout='30'>\r\n  
<s:AttributeType name='ows_Article_x0020_Tags' rs:name='Article Tags' rs:number='1'>\r\n   

我需要輸出作爲

string result= 14;#cricket;#21;#Headlines;#19;#Videos;20;#Charity;#14;#cricket 

即我需要的TXT躺在

之間

`<z:row ows_Article_x0020_Tags=" and " ows__ModerationStatus=` 

我試過用linq。我無法做到這一點。所以我想用正則表達式來做。是否有可能刪除字符串中除了使用正則表達式的結果之外的所有其他內容？

Answer 1

因此你沒有有效的XML在這裏，你可以把這個字符串作爲html和（來自的NuGet可）與HTMLAgilityPack解析它：

HtmlDocument hdoc = new HtmlDocument(); 
hdoc.LoadHtml(xmlstring); 
var tags = hdoc.DocumentNode.Descendants() 
       .Select(r => r.GetAttributeValue("ows_Article_x0020_Tags", "")); 

string result = String.Join("", tags); 
// 14;#cricket;#21;#Headlines;#19;#Videos20;#Charity;#14;#cricket 

隨着解析有效的XML推薦的工具是LINQ到XML 。解析應該看起來像：

XDocument xdoc = XDocument.Parse(validXmlString); 
XNamespace z = "#RowsetSchema"; 
var tags = xdoc.Descendants(z + "row") 
       .Select(r => (string)r.Attribute("ows_Article_x0020_Tags")); 

Answer 2

我通常使用LINQ從XML中獲取值，這使得它更容易。

例1：LINQ to read XML

例2：我用下面讓問題和答案的列表測驗應用

public List<QuizQuestions> GetQuiz(int level) 
    { 
     string docName = "DataModel/Level" + level.ToString() + ".xml"; 
     XDocument xdoc = XDocument.Load(docName); 
     List<QuizQuestions> book = (from list in xdoc.Descendants("Question") 
            select new QuizQuestions(list.Element("Quest").Value 
                  , list.Element("A").Value 
                  , list.Element("B").Value 
                  , list.Element("C").Value 
                  , list.Element("D").Value 
                  , list.Element("Answer").Value) 
                  ).OrderBy(a => Guid.NewGuid()).ToList(); 
     return book; 
    } 

UPDATE：這將有效的XML只工作

Answer 3

我不能強調如何不好一個想法，它是從正則表達式提取xml值，但如果你真的想這應該工作：

 Regex regex = new Regex("ows_Article_x0020_Tags='([^']*)'"); 
     var matches = regex.Matches(xmlstring); 
     Console.WriteLine(matches[0].Groups[1].Value); 
     Console.WriteLine(matches[1].Groups[1].Value);