如何Employee數據，基於部門計數

Question

我有EMP表進行排序..
伊諾的ename工資deptmentid
101亞歷2000 10

喜歡我有1000名員工的數據，有23個不同的部門..現在我的要求是以這樣的方式對數據進行排序，即哪個部門的數量最高。的員工..

例如，部門50有45名員工（所有部門中最高），那麼這45名員工應該列在第一位。部門-12有3名員工，那麼這3名員工應該被列在最後的聘用表..

Answer 1

SELECT Eno, Ename, Salary, E.deptmentid 
FROM EMP E INNER JOIN 
       (SELECT deptmentid, COUNT(Ename) TotalEmps 
       FROM EMP 
       GROUP BY deptmentid) Sub 
ON E.deptmentid = Sub.deptmentid 
ORDER BY TotalEmps DESC 

Answer 2

嘗試這樣的事情，

Declare @Emp table (Eno int, Ename varchar(50), Salary int, deptmentid int) 

insert into @Emp values(1,'cvxcv',3,45),(2,'uyyudfdf',3,45),(3,'hhgcvxcv',3,45),(4,'wewecvxcv',3,46) 
,(5,'sscvxcv',3,46),(6,'nmmcvxcv',3,47),(7,'erewr',3,47) 

select *,dense_rank()over(order by deptmentid)rn from @Emp 

Answer 3

這是使用窗口功能的好機會：

select e.* 
from (select e.*, count(*) over (partition by departmentmentid) as DepartmentCount 
     from emp e 
    ) e 
order by DepartmentCount desc, DepartmentId; 

請注意按DepartmentId排序以及計數。如果兩個部門的人數相同，那麼這將使部門之間的員工聚集在一起。

您也可能會喜歡：

select e.*, row_number() over (partition by departmentid order by newid()) as CounterInDepartment 
. . . 

此列舉每個部門內的員工。

Answer 4

select employee.name, employee.job, employee.deptmentid, 
    count(*) over(partition by deptmentid) as [count] 
from EMPLOYEE 
order by [count] desc, deptmentid