如何在urllib中捕獲404錯誤？ （python 3）

Question

我一直在閱讀數十個類似問題的例子，但是我無法獲得我見過的任何解決方案或其變體運行。我是屏幕抓取，我只想忽略404錯誤（跳過頁面）。我得到

'AttributeError：'module'object has no attribute'HTTPError'。

我試過'URLError'。我已經看到接近相同的語法作爲工作答案。有任何想法嗎？下面是我得到了什麼：

import urllib 
import datetime 
from bs4 import BeautifulSoup 

class EarningsAnnouncement: 
    def __init__(self, Company, Ticker, EPSEst, AnnouncementDate, AnnouncementTime): 
     self.Company = Company 
     self.Ticker = Ticker 
     self.EPSEst = EPSEst 
     self.AnnouncementDate = AnnouncementDate 
     self.AnnouncementTime = AnnouncementTime 

webBaseStr = 'http://biz.yahoo.com/research/earncal/' 
earningsAnnouncements = [] 
dayVar = datetime.date.today() 
for dte in range(1, 30): 
    currDay = str(dayVar.day) 
    currMonth = str(dayVar.month) 
    currYear = str(dayVar.year) 
    if (len(currDay)==1): currDay = '0' + currDay 
    if (len(currMonth)==1): currMonth = '0' + currMonth 
    dateStr = currYear + currMonth + currDay 
    webString = webBaseStr + dateStr + '.html' 
    try: 
     #with urllib.request.urlopen(webString) as url: page = url.read() 
     page = urllib.request.urlopen(webString).read() 
     soup = BeautifulSoup(page) 
     tbls = soup.findAll('table') 
     tbl6= tbls[6] 
     rows = tbl6.findAll('tr') 
     rows = rows[2:len(rows)-1] 
     for earn in rows: 
      earningsAnnouncements.append(EarningsAnnouncement(earn.contents[0], earn.contents[1], 
      earn.contents[3], dateStr, earn.contents[3])) 
    except urllib.HTTPError as err: 
     if err.code == 404: 
      continue 
     else: 
      raise 

    dayVar += datetime.timedelta(days=1) 

Answer 1

它看起來像urllib的（不是的urllib2），例外是urllib.error.HTTPError，不urllib.HTTPError。有關更多信息，請參閱documentation。