如何通過在陣列中的多個搜索參數在PHP搜索

Question

蔭在PHP寫我的代碼和我的數組看起來像這樣

$arr=Array 
(
[0] => Array 
    (
     [Business_name] => 1847(Jumeirah) 
     [Business_id] => 1422 
     [Business_Locality] => Jumeirah 
     [Locality_id] => 2 
    ) 

[1] => Array 
    (
     [Business_name] => 1847 Mens Salon(Trade Centre) 
     [Business_id] => 42 
     [Business_Locality] => Trade Centre 
     [Locality_id] => 4 
    ) 

[2] => Array 
    (
     [Business_name] => 1847 Mens Salon(Mirdif) 
     [Business_id] => 1565 
     [Business_Locality] => Mirdif 
     [Locality_id] => 28 
    ) 

[3] => Array 
    (
     [Business_name] => 1847 Mens Salon(City Walk) 
     [Business_id] => 494 
     [Business_Locality] => City Walk 
     [Locality_id] => 77 
    ) 

[4] => Array 
    (
     [Business_name] => 1847 Mens Salon(Dubai Marina) 
     [Business_id] => 44 
     [Business_Locality] => Dubai Marina 
     [Locality_id] => 3 
    )) 

現在，如果我要得到誰擁有Locality_id = 2的數據，但如果我想要搜索locality_id = 2和locality_id = 3的數據。因此，當結果集返回時，它應該只有locality_id = 2和locality_id = 3的數據。 我該怎麼做。

這是我寫到目前爲止

function search($array, $key, $value) 
{ 
$results = array(); 

if (is_array($array)) { 
    if (isset($array[$key]) && $array[$key] == $value) { 
     $results[] = $array; 
    } 

    foreach ($array as $subarray) { 
     $results = array_merge($results, search($subarray, $key, $value)); 
    } 
} 

return $results; 
    } 



    print_r(search($arr, 'Locality_id', '2')); 

Answer 1

這將幫助您獲得您的結果

$check = array(2,3); 
$result_array = array(); 
$i = 0; 
foreach ($arr as $itemKey => $itemValue) { 

     if (in_array($itemValue['Locality_id'],$check)) { 
      $result_array[$i]['Business_name'] = $itemValue['Business_name']; 
      $result_array[$i]['Business_id'] = $itemValue['Business_id']; 
      $result_array[$i]['Business_Locality'] = $itemValue['Business_Locality']; 
      $result_array[$i]['Locality_id'] = $itemValue['Locality_id']; 
     }else{ 
      continue; 
     } 
     $i++; 
} 
print_r($result_array); 

輸出：

Array ([0] => Array ([Business_name] => 1847(Jumeirah) [Business_id] => 1422 [Business_Locality] => Jumeirah [Locality_id] => 2) [1] => Array ([Business_name] => 1847 Mens Salon(Dubai Marina) [Business_id] => 44 [Business_Locality] => Dubai Marina [Locality_id] => 3)) 

Answer 2

聞起來像家庭作業的代碼。但是無所謂。如果我理解正確的問題，這應該這樣做：

$lookingFor = array(2,3); 

foreach($thisArray as $key => $value) { 
    foreach($lookingFor as $looking) { 
     if(in_array($looking, $value['Locality_id'])) { 
      $output[] = $value; 
      continue; 
     } 
    } 
} 

print_r($output); 

我還不測試，我的開發是下個大氣壓，但它應該工作，或至少是正確的方向。你應該可以自己調整代碼。