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我試圖打印出每個單獨行中最大路徑的輸出。在python中打印出單獨的行輸出
的代碼是在這裏:
def triangle(rows):
PrintingList = list()
for rownum in range (rows):
PrintingList.append([])
newValues = map(int, raw_input().strip().split())
PrintingList[rownum] += newValues
return PrintingList
def routes(rows,current_row=0,start=0):
for i,num in enumerate(rows[current_row]):
if abs(i-start) > 1:
continue
if current_row == len(rows) - 1:
yield [num]
else:
for child in routes(rows,current_row+1,i):
yield [num] + child
testcases = int(raw_input())
output = []
for num in range(testcases):
rows= int(raw_input())
triangleinput = triangle(rows)
max_route = max(routes(triangleinput),key=sum)
output.append(sum(max_route))
print '\n'.join(output)
我嘗試這樣做:
2
3
1
2 3
4 5 6
3
1
2 3
4 5 6
當我嘗試輸出出來的值,我得到這個:
print '\n'.join(output)
TypeError: sequence item 0: expected string, int found
如何變化這個?需要一些指導...
任何其它的辦法只有打印爲INT ...... – lakesh
輸出有打印整數,沒有什麼區別將其轉換爲字符串然後打印它(就像我的例子)。當你打印一個整數時,它會在幕後轉換爲一個字符串。 – grc