我在Windows上的Visual Studio中編寫了一個程序,程序編譯正確,但沒有將所需的輸出顯示到控制檯。但是,如果我在Linux上的Gedit中編譯和運行該程序,則會顯示正確的輸出並且一切正常。爲什麼是這樣?代碼如下:C++代碼在Gedit中工作,但不在VS中
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
string input;
cout << "College Admission Generator\n\n";
cout << "To begin, enter the location of the input file (e.g. C:\\yourfile.txt):\n";
cin >> input;
ifstream in(input.c_str());
if (!in)
{
cout << "Specified file not found. Exiting... \n\n";
return 1;
}
char school, alumni;
double GPA, mathSAT, verbalSAT;
int liberalArtsSchoolSeats = 5, musicSchoolSeats = 3, i = 0;
while (in >> school >> GPA >> mathSAT >> verbalSAT >> alumni)
{
i++;
cout << "Applicant #: " << i << endl;
cout << "School = " << school;
cout << "\tGPA = " << GPA;
cout << "\tMath = " << mathSAT;
cout << "\tVerbal = " << verbalSAT;
cout << "\tAlumnus = " << alumni << endl;
if (school == 'L')
{
cout << "Applying to Liberal Arts\n";
if (liberalArtsSchoolSeats > 0)
{
if (alumni == 'Y')
{
if (GPA < 3.0)
{
cout << "Rejected - High school Grade is too low\n\n";
}
else if (mathSAT + verbalSAT < 1000)
{
cout << "Rejected - SAT is too low\n\n";
}
else
{
cout << "Accepted to Liberal Arts!!\n\n";
liberalArtsSchoolSeats--;
}
}
else
{
if (GPA < 3.5)
{
cout << "Rejected - High school Grade is too low\n\n";
}
else if (mathSAT + verbalSAT < 1200)
{
cout << "Rejected - SAT is too low\n\n";
}
else
{
cout << "Accepted to Liberal Arts\n\n";
liberalArtsSchoolSeats--;
}
}
}
else
{
cout << "Rejected - All the seats are full \n";
}
}
else
{
cout << "Applying to Music\n";
if (musicSchoolSeats>0)
{
if (mathSAT + verbalSAT < 500)
{
cout << "Rejected - SAT is too low\n\n";
}
else
{
cout << "Accepted to Music\n\n";
musicSchoolSeats--;
}
}
else
{
cout << "Rejected - All the seats are full\n";
}
}
cout << "*******************************\n";
}
return 0;
}
感謝您的任何和所有幫助!
編輯:刪除絨毛。
爲了澄清,該程序在VS編譯。它打開文件,但不會回顯文件中的任何信息,而只是打印「按任意鍵退出...」。信息。
你看到了什麼錯誤信息?它編譯了嗎?也許你只需要包括'#include'? –
wally
它在哪裏不起作用,它究竟如何不起作用,與編輯器無關,可能是錯誤的文件,也可能是編譯器等 –