SQLite和蟒蛇時間戳

Question

我在Python 2.4的代碼：

import datetime, time, sqlite 
def metodo(date): 
     conn = sqlite.connect('dataBase.db') 
     c = conn.cursor() 
     c.execute("INSERT INTO f values(?,?)", (3,date)) 
     conn.commit() 
     conn.close() 

end_date=datetime.datetime(2012, 10, 21, 0, 0) 
print end_date 

metodo(end_date) 

與int和TIMESTAMP

create table f(id int, time TIMESTAMP) 

SQLite數據庫，但我得到這個在python：

Traceback (most recent call last): 
File "prueba.py", line 13, in ? 
metodo(end_date) 
File "prueba.py", line 6, in metodo 
c.execute("INSERT INTO f values(?,?)", (3,date)) 
File "/usr/lib/python2.4/site-packages/sqlite/main.py", line 255, in execute 
self.rs = self.con.db.execute(SQL % parms) 
TypeError: not all arguments converted during string formatting 

---

此代碼運行良好。問題是與時間戳：

import datetime, time, sqlite 
def metodo(date): 
     conn = sqlite.connect('dataBase.db') 
     c = conn.cursor() 
     c.execute("INSERT INTO a values(%s)", date) 
     conn.commit() 
     conn.close() 


metodo("stringTest") 

與int和TIMESTAMP

create table a(test text) 

Answer 1

SQLite數據庫我想你應該參數是這樣的：

def metodo(date): 
     conn = sqlite.connect('dataBase.db') 
     c = conn.cursor() 
     c.execute("INSERT INTO a values(%s)", (date,)) 
     conn.commit() 
     conn.close()