MySQL - 組和總數，但返回每個組中的所有行

Question

我正在嘗試編寫一個查詢，查找每次在特定日期範圍內發生在我的表中的同一個人。然後它將這個人分組並且將他們的花費總計在特定範圍內。如果他們的消費習慣大於X金額，則在指定的日期範圍內爲此人返回每一行。不僅僅是分組總量。這是我到目前爲止：

SELECT member_id, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50 

這是檢索正確的總和返回成員花費超過50美元，但不是每一行。只是每個成員的總數和他們的總數。我目前正在查詢整個表格，我沒有添加日期範圍。

Answer 1

JOIN這個子查詢與原表：

SELECT si1.* 
FROM sold_items AS si1 
JOIN (SELECT member_id 
     FROM sold_items 
     GROUP BY member_id 
     HAVING SUM(amount) > 50) AS si2 
ON si1.member_id = si2.member_id 

一般的規則是由同一列（S）的子查詢組，它的選擇，然後你加入那與原始查詢我們在同一列。

Answer 2

有幾種語法可以得到您要查看的結果，下面是使用內部聯接來確保返回的所有行在由組返回的列表中具有member_id並且總計爲每個某成員有：

SELECT si.*, gb.total from sold_items as si, (SELECT member_id as mid, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50) as gb where gb.mid=si.member_id; 

Answer 3

SELECT member_id, amount 
FROM sold_items si 
INNER JOIN (SELECT member_id, 
SUM(amount) AS total 
FROM `sold_items` 
GROUP BY member_id 
HAVING total > 50) spenders USING (member_id) 

您已經構建的查詢可以用作臨時表來加入。如果member_id不是表格中的索引，則這將隨着比例變慢。 單詞spenders是一個表別名，您可以使用任何有效的別名代替它。

Answer 4

我認爲，這可能幫助：

SELECT 
    member_id, 
    SUM(amount) AS amount_value, 
    'TOTAL' as amount_type 
FROM 
    `sold_items` 
GROUP BY 
    member_id 
HAVING 
    SUM(amount) > 50 

UNION ALL 

SELECT 
    member_id, 
    amount AS amount_value, 
    'DETAILED' as amount_type 
FROM 
    `sold_items` 
    INNER JOIN 
    (
     SELECT 
      A.member_id, 
      SUM(amount) AS total 
     FROM 
      `sold_items` A 
     GROUP BY 
      member_id 
     HAVING 
      total <= 50 
    ) AS A 
    ON `sold_items`.member_id = A.member_id 

上述查詢的結果應該是這樣的：

member_id  amount_value amount_type 
========================================== 
1    55    TOTAL 
2    10    DETAILED 
2    15    DETAILED 
2    10    DETAILED 

所以列amount_type將區分兩個特定成員組

Answer 5

你可以用EXISTS做子查詢：

select * 
from sold_items t1 
where exists (
    select * from sold_items t2 
    where t1.member_id=t2.member_id 
    group by member_id 
    having sum(amount)>50 
) 

ref：http://dev.mysql.com/doc/refman/5.7/en/exists-and-not-exists-subqueries.html