JSLint：如何不在循環內使這個函數

Question

在我的角度應用程序中，我使用循環在對象中查找給定數字的最近值並返回其密鑰。

例如，我想最接近值0.5：

for (var j in nums) { 
     if (0.5 > nums[j]) var prev = nums[j]; 
     else if (0.5 <= nums[j]) { 
     // If the current number is equal to 0.5, or immediately higher, stores that number 
     // and stops the for each() loop 
     var next = nums[j]; 
     // Get the value 
     var percentage = (Math.abs(0.5 - prev) < Math.abs(next - 0.5)) ? prev : next; 
     // Get the key from the value 
     $scope.seventyfive = parseInt('0' + Object.keys(nums).filter(function(key) {return nums[key] === percentage;})[0], 10); 
     break; 
     } 
    } 

JSLint的是指出，我不應該在一個循環中做功能，所以我試圖避免與：

filterPct = function (nums, pct) { 
     return function() { 
     return nums[key] === pct; 
     }; 
    } 

和

for (var j in nums) { 
     if (0.5 > nums[j]) var prev = nums[j]; 
     else if (0.5 <= nums[j]) { 
     // If the current number is equal to 0.5, or immediately higher, stores that number 
     // and stops the for each() loop 
     var next = nums[j]; 
     // Get the value 
     var percentage = (Math.abs(0.5 - prev) < Math.abs(next - 0.5)) ? prev : next; 
     // Get the key from the value 
     $scope.seventyfive = parseInt('0' + Object.keys(nums).filter(filterPct(nums, percentage))[0], 10); 
     break; 
     } 
    } 

但這返回0，而不是正確的值。我肯定我失去了一些東西很明顯，但我顯然需要另一雙眼睛......

UPDATE：感謝給了我支持，這是代碼的防錯以上版本：

filterPct = function (nums, pct) { 
     return function (key) { 
     return nums[key] === pct; 
     }; 
    }; 

    // Store the value with 50% Confidence 
    for (i in nums) { 
     if (nums.hasOwnProperty(i)) { 
     if (0.5 > nums[i]) { 
      prev = nums[i]; 
     } else if (0.5 <= nums[i]) { 
      // If the current number is equal to 0.5, or immediately higher, stores that number 
      // and stops the for each() loop 
      next = nums[i]; 
      // Get the value 
      percentage = (Math.abs(0.5 - prev) < Math.abs(next - 0.5)) ? prev : next; 
      // Get the key from the value 
      $scope.fifty = parseInt('0' + Object.keys(nums).filter(filterPct(nums, percentage))[0], 10); 
      break; 
     } 
     } 
    } 

Answer 1

filterPct = function (nums, pct) { 
    return function() { 
     return nums[key] === pct; 
    }; 
} 

你忘了定義key（應該是內部函數的第一個參數）。