從json獲取數據並僅使用一個結果作爲值

Question

我試圖使用www.football-data.org獲得足球聯賽積分榜，但是我從未使用過JSON。

我目前使用下列內容：

$uri = 'http://api.football-data.org/v1/soccerseasons/398/leagueTable/'; 
$reqPrefs['http']['method'] = 'GET'; 
$reqPrefs['http']['header'] = 'X-Auth-Token:'.$api_key; 

$stream_context = stream_context_create($reqPrefs); 

$response = file_get_contents($uri, false, $stream_context); 
$details = json_decode($response); 

，試圖讓細節的一個團隊。目前，我正在使用：

echo "<pre>"; 
print_r($details); 
echo "</pre>"; 

得到以下顯示：

stdClass Object 
(
    [_links] => stdClass Object 
     (
      [self] => stdClass Object 
       (
        [href] => http://api.football-data.org/v1/soccerseasons/398/leagueTable/?matchday=26 
       ) 

      [soccerseason] => stdClass Object 
       (
        [href] => http://api.football-data.org/v1/soccerseasons/398 
       ) 

     ) 

    [leagueCaption] => Premier League 2015/16 
    [matchday] => 26 
    [standing] => Array 
     (
      [0] => stdClass Object 
       (
        [_links] => stdClass Object 
         (
          [team] => stdClass Object 
           (
            [href] => http://api.football-data.org/v1/teams/338 
           ) 

         ) 

        [position] => 1 
        [teamName] => Leicester City FC 
        [crestURI] => http://upload.wikimedia.org/wikipedia/en/6/63/Leicester02.png 
        [playedGames] => 25 
        [points] => 53 
        [goals] => 47 
        [goalsAgainst] => 27 
        [goalDifference] => 20 
        [wins] => 15 
        [draws] => 8 
        [losses] => 2 
        [home] => stdClass Object 
         (
          [goals] => 21 
          [goalsAgainst] => 13 
          [wins] => 7 
          [draws] => 4 
          [losses] => 1 
         ) 

        [away] => stdClass Object 
         (
          [goals] => 26 
          [goalsAgainst] => 14 
          [wins] => 8 
          [draws] => 4 
          [losses] => 1 
         ) 

       ) 

首先，我怎麼去獲得這些值，並將其保存在PHP可用的變量？

其次，是否有可能將這些數據縮小到一個團隊？例如說：

if($details->teamName == 'Manchester United') { $gamesPlayed = $details->gamesPlayed; } 

Answer 1

你有其中有（其中包括）對象的數組命名爲standing和他們又將有teamName屬性的對象。所以，讓你會做

if($details->standing[0]->teamName == 'Manchester United') 

第一個或者你也可以遍歷standing，讓所有的人，如果萬一有多個條目

像

foreach($details->standing as $record) 
{ 
    if($record->teamName == 'Manchester United') 
     $gamesPlayed=$record->playedGames; 
}