錯誤在PHP如果

Question

語法錯誤意外，如果

$data = array(); 
$data['measure'] = ''; 
    $measure=$db->execute("select measure from measures where delet='0'"); 
    while($msrevalues=$measure->fetch_assoc()) 
    { 
     $data['measure'] .= '<option value="'.$msrevalues['measure'].'"'. if($tqmsre['measure']==$msrevalues['measure']){ echo "selected";}. '>'.$msrevalues['measure'].'</option>'; 
    } 
echo json_encode($data);exit(); 

什麼是錯誤在這個if語句..？
請幫助我......

Answer 1

執行if語句，而不是單獨的$數據

<?php 
$data = array(); 
$data['measure'] = ''; 
    $measure=$db->execute("select measure from measures where delet='0'"); 
    while($msrevalues=$measure->fetch_assoc()) 
    { 
     $selected = ($tqmsre['measure']==$msrevalues['measure']) ? 'selected="selected"' : ''; 
     $data['measure'] .= '<option value="'.$msrevalues['measure'].'" '. $selected. '>'.$msrevalues['measure'].'</option>'; 
    } 
echo json_encode($data); 
exit(); 
?>