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我需要輸入搜索數組的幫助。我試圖把二進制搜索,但我不能得到它的工作。一切工作,直到我把我在數組中搜索的值,然後它只是崩潰。搜索3d陣列
它是如何想的工作: 輸入2與座標值爲每個 然後計算它們之間的距離 那麼想,讓用戶搜索的座標值和狀態,如果發現哪個座標是偉大的。
感謝
#include "stdafx.h"
#include <iostream>
#include <iomanip> //for setprecision
#include <math.h>
#include <cstdbool>
#include <cstdlib> // Needed for rand and srand
#include <ctime> // Needed for the time function
using namespace std;
//Function Prototypes
void processThroughArray(int[][10][10], int, int, int, int, int, int);
int searchArray(int[][10][10], int, int, int, int, int, int, int, int);
const int SIZE = 10;
int main()
{
// establish array and set all values to 0
int myArray[10][10][10] = { 0 };
// establish x and y position markers
int x = 0;
int y = 0;
int z = 0;
int x2 = 0;
int y2 = 0;
int z2 = 0;
// establish input for x and y from the user
int xInput = 0;
int yInput = 0;
int zInput = 0;
int xInput2 = 0;
int yInput2 = 0;
int zInput2 = 0;
// variable for value entered
int inputValue = 0;
int inputValue2 = 0;
double distance = 0;
int searchValue;
int result;
// Get the user's value and coordinate
cout << "\nPlease enter the x coordinate ";
cin >> xInput;
cout << "\nPlease enter the y coordinate ";
cin >> yInput;
cout << "\nPlease enter the z coordinate ";
cin >> zInput;
cout << "\nPlease enter the value to place in " << xInput << "," << yInput << "," << zInput << " ";
cin >> inputValue;
// Get the user's ending value and coordinate
cout << "\nPlease enter the ending x coordinate ";
cin >> xInput2;
cout << "\nPlease enter the ending y coordinate ";
cin >> yInput2;
cout << "\nPlease enter the ending z coordinate ";
cin >> zInput2;
cout << "\nPlease enter the value to place in " << xInput2 << "," << yInput2 << "," << zInput2 << " ";
cin >> inputValue2;
// place the value in the coordinate
myArray[xInput][yInput][zInput] = inputValue;
cout << "\nYou have successfully placed the value " << inputValue << " in coordinate " << xInput << ", " << yInput << ", " << zInput << " ";
myArray[xInput2][yInput2][zInput2] = inputValue2;
cout << "\nYou have successfully placed the value " << inputValue2 << " in coordinate " << xInput2 << ", " << yInput2 << ", " << zInput2 << " ";
//Function performing for loop
processThroughArray(myArray, x, y, z, x2, y2, z2);
//calculate distance between the two coordinates
distance = sqrt(pow(xInput2 - xInput, 2.0) + pow(yInput2 - yInput, 2.0) + pow(zInput2 - zInput, 2.0));
cout << "\nThe distance between " << xInput << "," << yInput << "," << zInput << " and " << xInput2 << "," << yInput2 << "," << zInput2 << " is ";
cout << setprecision(4) << distance << endl;
// indicate end of array processing
cout << "\nArray Processed" << endl;
//User inputs value to search for
cout << "Enter the value you wish to look for: ";
cin >> searchValue;
result = searchArray(myArray, SIZE, searchValue, x, y, z, x2, y2,z2);
//If results contains a -1 the value not found
if (result == -1)
{
cout << "That number does not exists in the array.\n";
}
else
{
cout << "\nValue " << searchValue;
cout << " is located at position: " << result << endl;
}
system("pause");
return 0;
}
//**************************************************************************
// Definition of function processThroughArray: Process through the array *
//the for loop *
//**************************************************************************
void processThroughArray(int myArray[][10][10], int x, int y, int z, int x2, int y2, int z2)
{
for (int x = 0, x2 = 0; x<10, x2 < 10; x++, x2++)
{
for (int y = 0, y2 = 0; y<10, y2 < 10; y++, y2++)
{
for (int z = 0, z2 = 0; z< 10, z2 < 10; z++, z2++)
{
// Display the value of the coordinate
cout << "\nCordinate " << x << ", " << y << ", " << z << " value is " << myArray[x, x2][y, y2][z, z2];
}
}
}
}
//**************************************************************************
// Definition of function searchArray: search array for the value input *
// *
//**************************************************************************
int searchArray(int myArray[][10][10], int size, int value,int x, int y, int z, int x2, int y2, int z2)
{
int index = 0;
int position = -1;
bool found = false;
while (index < size && !found)
{
if (myArray[index][index][index] == value)
{
found = true;
position = index;
}
index++;
}
return position;
}
這裏有一個更新。 我已經通過線性搜索,但不是很確定我在這裏做錯了什麼。 我目前遇到的問題是它沒有正確地搜索數組。 它找到第一個數字,但找不到第二個數字。 也仍然不能把它放在座標上,但我相信我需要重點解決第一部分,然後再繼續。 謝謝,安吉拉 – eDz 2014-10-08 19:19:32
*更新了上面的代碼。 – eDz 2014-10-08 19:29:58
代碼的新版本將檢查myArray [0] [0] [0],然後myArray [1] [1] [1]等,直到myArray [9] [9] [9]。它將僅搜索數組中的十個元素,並完全忽略其他990.因此,除非您正在搜索只能在這10個座標中找到的內容,否則您不會找到它。 – 2014-10-08 22:33:10