寫入抄送數據到csv

Question

我一直卡住試圖將我刮到的數據傳輸到一個CSV文件。這裏是我的代碼：

import requests, bs4, csv, sys 
reload(sys) 
sys.setdefaultencoding('utf-8') 
url = 'http://www.constructeursdefrance.com/resultat/?dpt=01' 

res = requests.get(url) 
res.raise_for_status() 
soup = bs4.BeautifulSoup(res.text,'html.parser') 
links = [] 

for div in soup.select('.link'): 
    link = div.a.get('href') 
    links.append(link) 
for i in links: 
    url2 = i 
    res2 = requests.get(url2) 
    soup2 = bs4.BeautifulSoup(res2.text, 'html.parser') 
    for each in soup2.select('li > strong'): 
     data = each.text, each.next_sibling 
    with open('french.csv', 'wb') as file: 
     writer = csv.writer(file) 
     writer.writerows(data) 

輸出說：

Traceback (most recent call last): 
File "test_new_project.py", line 23, in <module> 
writer.writerows(data) 
csv.Error: sequence expected 

但我試圖把元組到CSV文件，只要我知道CSV接受元組和列表。我該如何解決這個問題？

Answer 1

Atirag是正確的，但你有另外一個問題是，你與調用打開輸出文件嵌套在一個for循環。因此，如果有多個鏈接，每次都會覆蓋該文件，並且輸出結果不符合您的期望。我想這應該生成你想要的輸出：

for div in soup.select('.link'): 
    link = div.a.get('href') 
    links.append(link) 

with open("french.csv", "w") as file: 
    writer = csv.writer(file) 
    for i in links: 
     res2 = requests.get(i) 
     soup2 = bs4.BeautifulSoup(res2.text, 'html.parser') 
     for each in soup2.select('li > strong'): 
      writer.writerow([each.text, each.next_sibling]) 

Answer 2

更改此

for each in soup2.select('li > strong'): 
     data = each.text, each.next_sibling 

這個

data=[] 
for each in soup2.select('li > strong'): 
     data.append((each.text, each.next_sibling)) 

數據變量是一個元組不是一個元組的列表。上面的代碼創建了一個元組列表。

其他的解決方案是這樣的（介意壓痕）

data = [] 
for i in links: 
    url2 = i 
    res2 = requests.get(url2) 
    soup2 = bs4.BeautifulSoup(res2.text, 'html.parser') 
    for each in soup2.select('li > strong'): 
     data.append((each.text, each.next_sibling)) 
with open('french.csv', 'wb') as file: 
    writer = csv.writer(file) 
    writer.writerows(data)