刪除紅寶石後從每行空格的字符串

Question

誰能幫我，如何從在紅寶石串的每一行刪除尾隨空格....例如：

str = "Hello everyone. \nHope you guys are doing good \nstrange i can't remove this spaces" 

我試着rstrip，但它不適合我....可能必須嘗試gsub ....我希望答案在下面wayy。

"Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces" 

Answer 1

str.split("\n").map(&:rstrip).join("\n") 

它可能與正則表達式是可行的，但我更喜歡這種方式。

Answer 2

您可以使用gsub!，這將改變接收器：使用另外一個gsub

str = "Hello everyone. \nHope you guys are doing good \nstrange i can't remove this spaces" 
str.gsub!(/\s\n/, "\n").inspect 
#=> "Hello everyone.\nHope you guys are doing good \nstrange i can't remove this spaces" 

Answer 3

或者這樣

str.each_line.map(&:strip).join("\n") 
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces" 

Answer 4

：

str.gsub(/\s+$/, '') 
#=> "Hello everyone.\nHope you guys are doing good\nstrange i can't remove this spaces" 

/\s+$/一個或多個空格匹配（\s+）就在之前換行符（$）