0
這對R腳本中的零經驗證明是一個怪物。我有57列,數據的30行的數據幀R函數用於計算某個值的頻率低於特定值的頻率
這裏就是我想要做:
1)到各列:
2)計數的時間2號/連續3/4/5/6/7/8/9值小於-1
3)打印結果作爲文本文件
4)重複步驟2和3的第二列,因此on
我環顧四周,也於r計算器
check number of times consecutive value appear based on a certain criteria
這是我的一列數據:
data<-c(-0.996,-1.111,-0.638,0.047,0.694,1.901,2.863,2.611,2.56,2.016,0.929,-0.153,-0.617,-0.143
0.199,0.556,0.353,-0.638,0.347,0.045,-0.829,-0.882,-1.143,-0.869,0.619,0.923,-0.474,0.227
0.394,0.789,1.962,1.132,0.1,-0.278,-0.303,-0.606,-0.705,-0.858,-0.723,-0.081,1.206,2.329
1.863,2.1,1.547,2.026,0.015,-0.441,-0.371,-0.304,-0.668,-0.953,-1.256,-1.185,-0.891,-0.569
0.485,0.421,-0.004,0.024,-0.39,-0.58,-1.178,-1.101,-0.882,0.01,0.052,-0.166,-1.703,-1.048
-0.718,-0.036,-0.561,-0.08,0.272,-0.041,-0.811,-0.929,-0.853,-1.047,0.431,0.576,0.642,1.62
2.324,1.251,1.384,0.195,-0.081,-0.335,-0.176,1.089,-0.602,-1.134,-1.356,-1.203,-0.795,-0.752
-0.692,-0.813,-1.172,-0.387,-0.079,-0.374,-0.157,0.263,0.313,0.975,2.298,1.71,0.229,-0.313
-0.779,-1.12,-1.102,-1.01,-0.86,-1.118,-1.211,-1.081,-1.156,-0.972)
當我運行下面的代碼:
for (col in 1:ncol(data)) {
runs <- rle(data[,col])
print(runs$lengths[which(runs$values < -1)])
}
它給我這個:
[1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
它已經計算了數值< -1但未運行。這是我在這裏錯了嗎?
感謝。我跑了腳本,但它沒有給我跑。我編輯了這個問題,以反映我的問題 – user53020 2014-10-10 14:45:28
更新了答案 – hrbrmstr 2014-10-10 14:53:20
謝謝,但這只是一個向量的權利?如果我需要對數據框中的所有列重複此操作,該怎麼辦? – user53020 2014-10-10 14:56:33