在其中一個練習中,我必須計算班級平均值。但我在這裏面臨一些問題。 計算班級平均數,我必須迭代每個正在通過的學生。 我的get_class_average()函數沒有按預期工作。儘管我用兩個學生名稱(愛麗絲,勞埃德)調用此函數,但只有愛麗絲得到處理,我的答案是來到91.15,而不是85.85 ...Python/Codeacademy:班級平均計算
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
# Add your function below!
def average(numbers):
total=sum(numbers)
total= float(total)
result = total/len(numbers)
return result
def get_average(student):
homework = 0.10 * average(student['homework'])
quizzes = 0.30 * average(student['quizzes'])
tests = 0.60 * average(student['tests'])
return (homework + quizzes +tests)
# This section is not working properly
def get_class_average(students):
results =[]
for item in students: <-- This loop may not be working
print item
result =get_average(item)
results.append(result)
print results
return average(results)
print get_class_average([alice,lloyd])
函數方法只能有一個'return'。你的'get_class_average'方法在for循環結尾處有一個return語句。您應該將每個人的平均值存儲在臨時列表中,然後將其返回。 –
iluengo:這不是真的。函數可以有多個'return'狀態。這只是導致錯誤的特定代碼。 – Nebril
嗯,真的,我在這個特殊情況下談論,而不是一般的編程。順便說一句,thx糾正。 –