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我正在使用這個類來抓取類中的所有td的內容。如何格式化這個被刪除的內容
$table01 = $salary->find('table.table01');
$rows = $table01[0]->find('td.job');
然後我使用這個輸出是其工作原理,但顯然只是將其作爲明文,我需要用它做一些更多...
foreach($table01[0]->find('td.job') as $element) {
$jobs .= $element->plaintext . '<br />';
}
最後,我想它輸出到這種格式。請注意,href正在使用作業名稱並將空格和/替換爲 - 。
<tr>
<td class="small"> <a href="/graphic-artist-designer">Graphic Artist/Designer</a>
$23,755 – $55,335 </td>
</tr>
<tr>
<td class="small"> <a href="/sales-associate">Sales Associate</a><br />
$15,577 – $56,290 </td>
</tr>
<tr>
<td class="small"> <a href="/film-video-editor">Film/Video Editor</a><br />
$24,184 – $94,493 </td>
</tr>
繼承人的表IM刮
<table cellpadding="0" cellspacing="0" border="0" class="table01">
<tr>
<td class="head">Test</td>
<td class="job">
<a href="/Graphic_Artist_%2f_Designer" id="UniqueID1">Graphic Artist/Designer</a><br/>
$23,755 – $55,335
</td>
</tr>
<tr>
<td class="head">Test</td>
<td class="job">
<a href="/Sales_Associate" id="UniqueID2">Sales Associate</a><br/>
$15,577 – $56,290
</td>
</tr>
<tr>
<td class="head">Test</td>
<td class="job">
<a href="/Film_%2f_Video_Editor" id="UniqueID3">Film/Video Editor</a><br/>
$24,184 – $94,493
</td>
</tr>
</table>