2017-04-03 25 views
0

我知道也許它可能是一個重複的問題,我在網上閱讀類似的帖子,但我不能發送我的輸入值從JSP到servlet。 我可以上傳文件,但我需要發送一個輸入值。 的Servlet:如何將輸入值從jsp中的multipart/form-data傳遞給servlet?

try { 
       FileItemIterator iterator = upload.getItemIterator(req); 
       while (iterator.hasNext()) { 
        FileItemStream item = iterator.next(); 
        InputStream in = item.openStream(); 


         if (item.isFormField()) { 
          out.println("Got a form field: " + item.getFieldName()); 


          } else { 
           String fieldName = item.getFieldName(); 
           String fileName = item.getName(); 
           String contentType = item.getContentType(); 
           String fileNameWithOutExt = FilenameUtils.removeExtension(fileName); 

           out.println("--------------"); 
           out.println("fileName = " + fileName); 
           out.println("Kind = " + fileNameWithOutExt); 
           out.println("field name = " + fieldName); 
           out.println("contentType = " + contentType); 

           String fileContents = null; 
           try { 

            fileContents = IOUtils.toString(in); 
            out.println("lenght: " + fileContents.length()); 

            String[] content = fileContents.split("\n"); 


            String[] property = content[0].split(","); 

            out.println("lunghezza " + property.length); 
            for (String propr : property) { 
             out.println("prop: " + propr); 
            } 
            //out.println(Arrays.toString(property)); 
            //out.println(fileContents); 
           } finally { 
            IOUtils.closeQuietly(in); 
              } 

            } 
              } 
       } catch (SizeLimitExceededException e) { 
        out.println("You exceeded the maximu size (" 
          + e.getPermittedSize() + ") of the file (" 
          + e.getActualSize() + ")"); 
                } 
      } catch (Exception ex) { 

       throw new ServletException(ex); 
           } 
                  } 

這就是我的JSP

<form action="/upload_kind" method="post" enctype="multipart/form-data" > 
<input type="file" name="file" size="50" /> 
<input type="text" name="namespace" id="namespace"> 
<br /> 
<input type="submit" value="Upload File" /> 
</form> 

我讀到了 「item.getString()」 方法,但它在DiskFileItem類,而不是在FileItemStream,這樣我就可以看到「命名空間「發送,但我看不到它的價值。 Thx和對不起我的英語不好

+0

你的輸入值是多少?如果這是命名空間,您應該可以通過request.getParameter(「namespace」)獲取它。 –

+0

它是命名空間,但我無法得到它的原因「multipart/form-data」。它返回null – ValeMarz

+1

[如何使用JSP/Servlet將文件上傳到服務器?](http://stackoverflow.com/questions/2422468/how-to-upload-files-to-server-using-jsp-servlet ) –

回答

0

重複鏈接後,我能解決我的問題。我用這個代碼:

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
    try { 
     List<FileItem> items = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request); 
     for (FileItem item : items) { 
      if (item.isFormField()) { 
       // Process regular form field (input type="text|radio|checkbox|etc", select, etc). 
       String fieldName = item.getFieldName(); 
       String fieldValue = item.getString(); 
       // ... (do your job here) 
      } else { 
       // Process form file field (input type="file"). 
       String fieldName = item.getFieldName(); 
       String fileName = FilenameUtils.getName(item.getName()); 
       InputStream fileContent = item.getInputStream(); 
       // ... (do your job here) 
      } 
     } 
    } catch (FileUploadException e) { 
     throw new ServletException("Cannot parse multipart request.", e); 
    } 

    // ... 
}