如何挑選的關鍵，在java中

Question

中的.txt文件及其相應的值這是我下面的.txt文件

.txt file

我想要檢索基於URl.I IP地址嘗試下面的代碼但它失敗了。我可以使用Hashmap。這是我的第一篇文章。我爲我的錯誤道歉。

公共靜態無效的主要（字符串ARGS []）拋出IOException異常{

FileReader fr = new FileReader("C:/Users/charan/Desktop/Resources/HashCheck.txt"); 
    BufferedReader br = new BufferedReader(fr); 
    Scanner in = new Scanner(System.in); 
    System.out.println("enter:"); 
    String output = in.next(); 
    String line; 

    while((line = br.readLine()) != null){ 
     if (line.contains(output)) 
     { 
      output = line.split(":")[1].trim(); 
      System.out.println(output); 
      break; 
     } 
     else 
      System.out.println("UrL not found"); 
     break; 
    } 
    in.close(); 

}} 

要刪除底部突破

Answer 1

public static void main(String args[]) throws IOException { 

    FileReader fr = new FileReader("C:/Users/charan/Desktop/Resources/HashCheck.txt"); 
    BufferedReader br = new BufferedReader(fr); 
    Scanner in = new Scanner(System.in); 
    System.out.println("enter:"); 
    String output = in.next(); 
    String line; 
    String myIp = null;      //assign a new variable to put IP into 
    while ((line = br.readLine()) != null) { 
     if (line.contains(output)) { 
      myIp = line.split(":")[1].trim(); //assign IP to the new variable 
      System.out.println(myIp); 
      break;       //break only if you get the IP. else let it iterate over all the elements. 
     } 
    } 
    in.close(); 
    if (myIp == null) {      //if the new variable is still null, IP is not found 
     System.out.println("UrL not found"); 
    } 
}