獲取有序散列

Question

我有一個模型如下

class Quote < ActiveRecord::Base 

    named_scope :from_affiliate_id, Proc.new { |id| 
    { :select => "COUNT(*) as count_all, date(created_at) as date_created_at", 
     :conditions => {:affiliate_id => id}, 
     :group => "date(created_at)", 

    } 
    } 
    named_scope :in_dates, Proc.new {|from,to|{ :conditions => ["date(created_at) >= ? and date(created_at) <= ?",from,to]}} 

    belongs_to :affiliate 

    def self.create_quote(value = '') 
    return if value.nil? 
    quote = self.new(:affiliate_id => value) 
    quote.save 
    end 

end 

當我做Quote.from_affiliate_id（1），我得到以下結果

[#<Quote >, #<Quote >, #<Quote >, #<Quote >] 

我想獲得一個有序的Hash代替。哪一個應該有一個日期作爲一個關鍵並計入價值。請幫助我。在預期

Answer 1

Quote.from_affiliate_id(1).inject({}) do |h,q| 
    h[q.created_at] = q.count_all 
    h 
end 

Answer 2

感謝嘗試

ActiveSupport::OrderedHash[*Quote.from_affiliate_id(1).map {|q| 
    [q.created_at, q.count_all] 
}.flatten] 

創建一個正常的哈希值不會被下令：

>> ActiveSupport::OrderedHash[4,3,2,1].to_a 
=> [[4, 3], [2, 1]] 

與

>> Hash[4,3,2,1].to_a 
=> [[2, 1], [4, 3]]