此代碼的工作,並且輸出按預期陣列的性能,但會引發以下錯誤信息:爲什麼這個代碼使用的MySQLi拋出一個PHP的通知:試圖讓非對象
PHP的通知:嘗試獲得非對象的屬性...
這裏是我的代碼:
$mysqli = new mysqli("localhost","user","pass","database");
$sql = "SELECT keyterm
FROM keyterms";
$results = $mysqli->query($sql);
while($result = $results->fetch_object()->keyterm)
$keyterms[] = $result;