我在網站上獲取公司和產品詳細信息。 它有div標籤,裏面有li標籤,我想要獲得div標籤中的所有li標籤。 我使用python 3.5.1和BeautifulSoup如何獲取div標籤中的所有li標籤
我的代碼:
from bs4 import BeautifulSoup
import urllib.request
import re
r = urllib.request.urlopen('http://i.cantonfair.org.cn/en/ExpExhibitorList.aspx?k=glassware')
soup = BeautifulSoup(r, "html.parser")
links = soup.find_all("a", href=re.compile(r"expexhibitorlist\.aspx\?categoryno=[0-9]+"))
linksfromcategories = ([link["href"] for link in links])
string = "http://i.cantonfair.org.cn/en/"
linksfromcategories = [string + x for x in linksfromcategories]
for link in linksfromcategories:
response = urllib.request.urlopen(link)
soup2 = BeautifulSoup(response, "html.parser")
links2 = soup2.find_all("a", href=re.compile(r"\ExpExhibitorList\.aspx\?categoryno=[0-9]+"))
linksfromsubcategories = ([link["href"] for link in links2])
linksfromsubcategories = [string + x for x in linksfromsubcategories]
for link in linksfromsubcategories:
response = urllib.request.urlopen(link)
soup3 = BeautifulSoup(response, "html.parser")
links3 = soup3.find_all("a", href=re.compile(r"\ExpExhibitorList\.aspx\?categoryno=[0-9]+"))
linksfromsubcategories2 = ([link["href"] for link in links3])
linksfromsubcategories2 = [string + x for x in linksfromsubcategories2]
for link in linksfromsubcategories2:
response2 = urllib.request.urlopen(link)
soup4 = BeautifulSoup(response2, "html.parser")
companylink = soup4.find_all("a", href=re.compile(r"\expCompany\.aspx\?corpid=[0-9]+"))
companylink = ([link["href"] for link in companylink])
companylink = [string + x for x in companylink]
for link in companylink:
response3 = urllib.request.urlopen(link)
soup5 = BeautifulSoup(response3, "html.parser")
companydetail = soup5.find_all("div", id="contact")
for element in companydetail:
companyname = element.a[0].get_text()
print (companyname)
companyaddress = element.a[1].get_text()
print (companyaddress)And I am getting error
而且我得到錯誤
Traceback (most recent call last):
File "D:\python\phase3.py", line 54, in <module>
lis = companydetail.find_all('li')
AttributeError: 'ResultSet' object has no attribute 'find_all'
它說的:
或者使用列表中理解的
companydetail
得到所有li
s的列表第54行有錯誤,但是您只包含了37行,其中沒有一行包含拋出錯誤的代碼。 – wpercy