您可以使用strings.FieldsFunc
,像這樣的工作示例代碼:
package main
import "fmt"
import "strings"
func find(input string) []string {
return strings.FieldsFunc(input, split)
}
func main() {
strs := find("p -(40) *(GOT) +(FF)")
str := strings.Replace(fmt.Sprint(strs), " ", ", ", -1)
fmt.Println(str)
}
func split(r rune) bool {
return r == ' ' || r == '-' || r == '(' || r == ')' || r == '*' || r == '+'
}
輸出:
[p, 40, GOT, FF]
您可以使用strings.Fields
然後strings.Trim
,像這樣的工作示例代碼:
package main
import "fmt"
import "strings"
func main() {
fmt.Println(find("p -(40) *(GOT) +(FF)"))
}
func find(input string) []string {
strs := strings.Fields(input)
result := make([]string, 0, len(strs))
for _, v := range strs {
s := strings.Trim(v, "()+-*")
if len(s) > 0 {
result = append(result, s)
}
}
return result
}
輸出:
[p 40 GOT FF]
而且這種方式更適合你的特殊情況:
package main
import "fmt"
import "strings"
func main() {
fmt.Println(find("p -(40) *(GOT) +(FF)"))
}
func find(input string) []string {
strs := strings.Fields(input)
for i := 0; i < len(strs); i++ {
strs[i] = strings.Trim(strs[i], "()+-*")
}
return strs
}
輸出:
[p 40 GOT FF]
如果你需要這樣的字符串輸出: [p, 40, GOT, FF]
,試試這個工作示例代碼:
package main
import "fmt"
import "strings"
func main() {
strs := find("p -(40) *(GOT) +(FF)")
str := strings.Replace(fmt.Sprint(strs), " ", ", ", -1)
fmt.Println(str)
}
func find(input string) []string {
strs := strings.Fields(input)
for i := 0; i < len(strs); i++ {
strs[i] = strings.Trim(strs[i], "()+-*")
}
return strs
}
輸出:
[p, 40, GOT, FF]
怎麼樣一個正則表達式? – tkausl
感謝您的回覆!有點難爲我,我是一個noobie編程.. – jiji
https://play.golang.org/p/dRfMfZhH7- –