示例Smooch.io PHP webhook

我有這個PHP webhook頁面，我正在使用我的示例smooch.io應用程序，請參閱下文。示例Smooch.io PHP webhook

<?php 

$content = file_get_contents("php://input"); 
$update = json_decode($content, true); 

if (!$update) { 
    // receive wrong update, must not happen 
    exit; 
} 

logf(json_encode($content)); 

/*curl https://api.smooch.io/v1/appusers/5790bff5237cbc5d00b10a17/conversation/messages \ 
    -X POST \ 
    -d '{"text":"Just put some vinegar on it", "role": "appMaker"}' \ 
    -H 'content-type: application/json' \ 
    -H 'authorization: Bearer your-jwt' 
*/ 
$parameters["text"] = "Reply from the webhook!"; 
$parameters["role"] = "appMaker"; 

$handle = curl_init("https://api.smooch.io/v1/appusers/5790bff5237cbc5d00b10a17/conversation/messages"); 
curl_setopt($handle, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($handle, CURLOPT_CONNECTTIMEOUT, 5); 
curl_setopt($handle, CURLOPT_TIMEOUT, 60); 
curl_setopt($handle, CURLOPT_POSTFIELDS, json_encode($parameters)); 
curl_setopt($handle, CURLOPT_HTTPHEADER, 
    array("Content-Type: application/json; charset=utf-8","Authorization: Bearer ".MY_JWT) 
); 

$response = curl_exec($handle); 
logf("response: ".$response); 
$response = json_decode($response, true); 

function logf($str){ 
    $logf = "smooch.txt"; 
    $dtnow = date("dmy H:i:s"); 
    $logfh = fopen($logf, 'a'); 
    $str = $dtnow." - ".$str."\n"; 
    fputs($logfh, $str); 
    fclose($logfh); 
}

我收到以下錯誤在我登錄響應

響應：{ 「錯誤」：{ 「代碼」：「user_not_found」，「說明」：「用戶未找到」}}

我在這裏驗證了我的簽名使用我懷疑從smooch.io

給出的憑證https://jwt.io/它的這個{smoochId |用戶id}值？我從瀏覽器的URL中複製了這些隨機字符（5790bff5237cbc5d00b10a17），我假設這是我的用戶ID。請告訴我如何獲得我的smoochID或userID。謝謝！

來源

2016-07-22 martti d

5790bff5237cbc5d00b10a17是您的應用程序ID，而不是您用戶的ID。要獲得用戶ID，您必須先初始化一個：

http://docs.smooch.io/rest/#init

來源

2016-07-23 18:41:24

示例Smooch.io PHP webhook

回答

相關問題