根據標題將字符串分割爲多個部分

Question

我想根據標題按照特定格式（==HEADER==）將字符串分割爲多個部分。這裏的輸入字符串會是什麼樣子：

== Section header == 
Text inside section 
=== Maybe a nested section === 
With some more text 
And more text 
==Then the next section header, perhaps w/o spaces between text and equals signs== 
With text inside it 

這是我想要的輸出：

[ 
    '== Section header == 
    Text inside section 
    === Maybe a nested section === 
    With some more text 
    And more text', 
    '==Then the next section header, without spaces between text and equals signs== 
    With text inside it' 
] 

我試圖做

pagetext = "== Test header ==\n Some test text, with random equals signs==newlines\n or whatever\n ==Another header == \n more text,\nnewlines\nohmy" 
sections = []; 
section_re = /==\s*(\s*[^=]*)\s*==/g; 
var section_headers = pagetext.match(section_re); 
for (var i = 0; i < section_headers.length; i++) { 
    var section_start = pagetext.indexOf(section_headers[i]); 
    var section_text = pagetext.substring(section_start); 
    if (i < section_headers.length - 1) { 
     var section_end = section_text.substring(section_headers[i].length).indexOf(section_headers[i + 1]) + section_headers[i].length; 
     section_text = section_text.substring(0, section_end); 
    } 
    sections.push(section_text); 
} 

但它分割在「隨機等號」跡象，給我：

["== Test header ==\n Some...ith random equals signs", "==newlines\n or whatever...ore text,\nnewlines\nohmy"] 

這不是 對。我有一種感覺，我的代碼可能太複雜 - 有沒有更好的方法來做到這一點？

Answer 1

有

result = subject.match(/^==[^=]*?==$((\r?\n?)(?!==[^=]).*)*/img); 

Answer 2

如果你感覺懶得做，你可以給這個一展身手：https://code.google.com/p/wiki2html/

我已經成功地使用過。