查詢以多個值爲基礎找到具有多個值的第二列的ID？

Question

我有以下的問題，我想從feature_values表中選擇的product_id其中variant_id等於多個值

我有這個

SELECT product_id FROM feature_values WHERE variant_id = '162' AND variant_id = '11819' 

以上的回報沒有結果

以下兩個查詢返回product_id

SELECT product_id FROM feature_values WHERE variant_id = '162' 

，這

SELECT product_id FROM feature_values WHERE variant_id = '11819' 

表例如數據

Feature ID, Product ID, Variant ID, Value 
     92,  565,  11815 
     69,  565,  162 
     92,  566,  11819 
     69,  566,  162 

Answer 1

嘗試這些了，是你正在尋找沒有什麼，邏輯思維變異ID可以是一方或另一方不能同時進行。

SELECT product_id FROM feature_values WHERE variant_id IN ('162', '11819') 

OR

SELECT product_id FROM feature_values WHERE variant_id = '162' OR variant_id = '11819' 

Answer 2

SELECT product_id FROM feature_values WHERE variant_id = '162' OR variant_id = '11819' 

或

SELECT product_id FROM feature_values WHERE variant_id in ('162','11819')