-2
這是整個項目,它應該盡我所能地看到,但我希望在這裏張貼它可以讓我看到我錯過的東西,我有一個溫和的與Java經驗量Java代碼將不會打印出答案或正確讀取int
package com.company;
import java.util.Random;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// write your code here
Scanner input = new Scanner(System.in);
int number1;
int number2;
int answer;
String operator;
此計算出的數字和運營商的用戶想要什麼
System.out.println("Please Enter your first number");
number1 = input.nextInt();
System.out.println("Please enter your second number");
number2 = input.nextInt();
System.out.println("Please enter your operator: + , - , * ,/");
operator = input.next();
if語句應該確定用戶希望其子及applys兩個數字,然後調用randomEquation方法使其成爲錯誤答案
if (operator == "+") {
answer = number1 + number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "-") {
answer = number1 - number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "*") {
answer = number1 * number2;
System.out.println("Your answer is: " + randomEquation(answer));
} else if (operator == "/") {
answer = number1/number2;
System.out.println("Your answer is: " + randomEquation(answer));
}
}
這種方法適用於隨機其中的一個答案創建錯誤的答案
public static int randomEquation(int number) {
Random rand = new Random();
int random = rand.nextInt(100) + 1;
int answer = number;
if (random <= 100 && random >= 81) {
answer = number * 25;
return answer;
}
else if(random <= 80 && random >= 61){
answer += 13;
return answer;
}
else if(random <= 60 && random >= 41){
answer /= 2;
return answer;
}
else if(random <= 40 && random >= 21){
answer -= 16;
return answer;
}
else{
answer %= 4;
return answer;
}
}
}