每次更新到mysql的html表格數組

Question

我一直在絞盡腦汁想出這幾天的結果，並且總結出來了。我想用下面的表單值來更新數據庫中的行：

<input type="text" name="item[]" maxlength="255" value="',htmlentities($item["item"]),'"> 
<input type="text" name="description[]" maxlength="255" value="',htmlentities($item["description"]),'"> 
<input type="text" name="rate[]" maxlength="10" value="',htmlentities($item["rate"]),'"> 
<input type="hidden" name="itemid[]" value="',htmlentities($item["id"]),'" /> 

這下面的數組回：

Array 
(
[item] => Array 
    (
     [0] => item listing 1 
     [1] => item listing 2 
    ) 

[description] => Array 
    (
     [0] => item testing description 
     [1] => item testing description 
    ) 

[rate] => Array 
    (
     [0] => 1.00 
     [1] => 2.00 
    ) 

[itemid] => Array 
    (
     [0] => 1 
     [1] => 2 
    ) 
) 

現在我試着用下面的，但更新到數據庫無濟於事我只能更新字段（[1]值）的最後一行:(任何幫助將是巨大的

if (is_array($values)) 
{ 
for ($i = 0; $i < count($values); $i++) 
{ 
    $item   = $values['item']; 
    $description = $values['description']; 
    $rate   = $values['rate']; 
    $id    = $values['itemid']; 

    // $query = "UPDATE `invoice_items` SET `item` = '{$item}', `description` = '{$description}', `rate` = '{$rate}' WHERE `id` = '{$id}';"; 
    // Setting query function here 
} 

Answer 1

添加子陣列數字了。

if (is_array($values)) 
{ 
for ($i = 0; $i < count($values); $i++) 
{ 
    $item   = $values['item'][$i]; 
    $description = $values['description'][$i]; 
    $rate   = $values['rate'][$i]; 
    $id    = $values['itemid'][$i]; 

    // $query = "UPDATE `invoice_items` SET `item` = '{$item}', `description` = '{$description}', `rate` = '{$rate}' WHERE `id` = '{$id}';"; 
    // Setting query function here 
} 

Answer 2

像這樣的事情？

if (is_array($values)) { 
    for ($i = 0; $i < count($values['itemid']); $i++) { 
     $item   = $values['item'][$i]; 
     $description = $values['description'][$i]; 
     $rate   = $values['rate'][$i]; 
     $id    = $values['itemid'][$i]; 

     $query = "UPDATE `invoice_items` SET `item` = '{$item}', `description` = '{$description}', `rate` = '{$rate}' WHERE `id` = '{$id}';"; 
     mysql_query($query); 
    } 
}