從另一個類的成員函數的類中的線程

Question

有人能告訴我怎樣才能運行一個新的線程與成員函數從不同類的對象作爲這個類的成員函數？什麼即時嘗試做我仍然得到錯誤。

no match for call to '(std::thread) (void (Boo::*)(), Boo&)'|
no match for call to '(std::thread) (void (Foo::*)(), Foo*)'|

#include <iostream> 
#include <thread> 
using namespace std; 
class Boo 
{ 
public: 
    void run() 
    { 
     while(1){} 
    } 
}; 

class Foo 
{ 
public: 
    void run() 
    { 
     t1(&Boo::run,boo); 
     t2(&Foo::user,this); 
    } 
    void user(); 
    ~Foo(){ 
     t1.join(); 
     t2.join(); 
    } 
private: 
    std::thread t1; 
    std::thread t2; 
    Boo boo; 
}; 
int main() 
{ 
    Foo foo; 
    foo.run(); 
} 

Answer 1

您需要使用operator=到建設

以下工作示例（see it in action）後分配線程：

#include <thread> 
#include <iostream> 

class Boo 
{ 
public: 
    void run() 
    { 
     int i = 10; 
     while(i--) 
     { 
      std::cout << "boo\n";; 
     } 
    } 
}; 

class Foo 
{ 
public: 
    void run() 
    { 
     t1 = std::thread(&Boo::run,boo); // threads already default constructed 
     t2 = std::thread(&Foo::user,this); // so need to *assign* them 
    } 

    void user() 
    { 
     int i = 10; 
     while(i--) 
     { 
      std::cout << "foo\n";; 
     } 
    } 

    ~Foo() 
    { 
     t1.join(); 
     t2.join(); 
    } 

private: 
    std::thread t1; 
    std::thread t2; 
    Boo boo; 
}; 

int main() 
{ 
    Foo foo; 
    foo.run(); 
}