使用貓鼬填充模型對象的數組

Question

這是我使用的模式。正如你所看到的，survey_codes模型路徑由一個ObjectIds數組組成。

... 
var Schema = mongoose.Schema; 
var Email = mongoose.SchemaTypes.Email; 
var ObjectId = mongoose.SchemaTypes.ObjectId; 

var RestaurantSchema = new Schema({ 
    id     : {type: String, required: true, unique: true}, 
    name     : {type: String, required: true}, 
    owner_name   : String, 
    reservation_email  : Email, 
    survey_url   : String, 
    survey_codes   : [{type: ObjectId, ref: SurveyCode}], 
    created_at   : {type: Date, default: Date.now} 
}); 

var SurveyCodeSchema = new Schema({ 
    code     : {type: String, unique: true, required: true}, 
    valid     : {type: Boolean, default: true}, 
    create_date   : {type: Date, default: Date.now}, 
    used_date    : {type: Date, default: null} 
}); 

在這裏，我想要的功能，使用方法：

Restaurant 
    .findOne({ id: self.param('id') }) 
    .populate('survey_codes') 
    .exec(function(err, restaurant) { 
     if (err) 
     console.log('Error in view survey codes function'); 
     if (!restaurant || restaurant.survey_codes.length < 1) 
     self.res.send('No survey codes are yet generated.'); 
     else 
     self.res.send(restaurant.survey_codes); 
    }); 

當我執行功能，它給了我這個錯誤：

Locomotive 0.3.7 application starting in development on http://0.0.0.0:3000 

/home/pblondin/nodejs-dev/rezerve-locomotive/node_modules/mongoose/lib/utils.js:419 
     throw err; 
      ^
MissingSchemaError: Schema hasn't been registered for model "function model(doc, fields, skipId) { 
    if (!(this instanceof model)) 
     return new model(doc, fields, skipId); 
    Model.call(this, doc, fields, skipId); 
    }". 

我只是」不要把我的頭放在這個上面。這是我第一次在這裏發佈，我注意到你們中的幾個人回答了類似的問題，但解決方案在我的情況下不起作用。

謝謝！

EDITED：

下面是一些附加信息：

1）從餐館採集的樣品：

[ 
    { 
     "__v": 1, 
     "_id": "52617861b9ee6c171b000001", 
     "id": "AAA", 
     "name": "Name", 
     "owner_name": "Owner", 
     "reservation_email": "email@new.com", 
     "survey_url": "new@new.com", 
     "created_at": "2013-10-18T18:05:21.447Z", 
     "survey_codes": [ 
      "52617864b9ee6c171b000002", 
      "52617864b9ee6c171b000003", 
      "52617864b9ee6c171b000004", 
      "52617864b9ee6c171b000005", 
      "52617864b9ee6c171b000006", 
      "52617864b9ee6c171b000007", 
      "52617864b9ee6c171b000008", 
      "52617864b9ee6c171b000009", 
      "52617864b9ee6c171b00000a", 
      "52617864b9ee6c171b00000b" 
     ] 
    } 
] 

2）的依賴關係的版本：

mongoose: 3.6.20 
mongodb: 1.3.19 
locomotive: 0.3.7 
locomotive-mongoose: 0.1.0 

Answer 1

解決（ ！）

一個簡單的錯字在我的模型：

survey_codes   : [{type: ObjectId, ref: SurveyCode}], 

裁判的是一個型號名稱，因此「SurveyCode」，而不是！