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中正常工作就像標題所示,我很難讓printf()
和echo
部分代碼正確輸出文本。無法使用printf()或echo在php
這裏的第一頁,一張簡單的表格:
<form action="WhoYouAre.html" method="post">
<Label>Name: <label><input type="text" name="name"><br>
<Label>Age: <label><input type="text" name="age"><br>
<Label>Address: <label><input type="text" name="address"><br>
<Label>State: <label><input type="text" name="state"><br>
<Label>Sex: <label><input type="text" name="sex"><br>
<input type="submit" value="Submit">
</form>
下面是針對的應該顯示的信息頁面的代碼:
<?php
session_start(); ?>
<?php
$_SESSION['name'] = $_POST['name'];
$_SESSION['age'] = $_POST['age'];
$_SESSION['address'] = $_POST['address'];
$_SESSION['state'] = $_POST['state'];
$_SESSION['sex'] = $_POST['sex'];
printf("Your name is %s.
Your age is %d.
Your address is %s, in the state of %s.
Your gender is %s.", $_SESSION['name'], $_SESSION['age'],
$_SESSION['address'], $_SESSION['state'], $_SESSION['sex']);
if($_SESSION['sex'] == 'male')
echo "<body style='background: url(http://images.mentalfloss.com/sites/default/files/styles/article_640x430/public/4hjh3kj634.png)'>";
echo file_get_contents("PostPage.txt");
?>
下面是輸出到我的網頁。
"; echo file_get_contents("PostPage.txt"); ?>
任何提示??
可能重複的[PHP代碼沒有被執行,而是代碼顯示在頁面上](http://stackoverflow.com/questions/5121495/php-code-is-not-being-executed-instead-code-顯示 - 上的頁面) –