bind_result失敗

Question

我實際上嘗試mysqli->fetch_array();獲取數組，但不能工作，所以我用bind_result（）;並且它拋出下面的錯誤

Warning: mysqli_stmt::bind_result(): Number of bind variables doesn't match number of fields in prepared statement

所以我做了一個bind_result錯誤檢查和我得到了什麼是bind_result() failed:等什麼我真的做錯了嗎？

$wtf = ""; 
$hello = ""; 
$check_empty_field = $mysqli - > prepare("select `username`, `firstname`, `lastname` from `vpb_uploads` where `username` = ? and `firstname` = ? and `lastname` = ?"); 
$check_empty_field - > bind_param('sss', $username, $wtf, $hello); 
$check_empty_field - > execute(); 
$check_empty_field - > store_result(); 
if($check_empty_field - > num_rows < 1) { 
    $date = date("d-m-Y"); 
    $i2 = ''; 
    $i3 = ''; 
    $i4 = ''; 
    $i5 = ''; 
    $insert = $mysqli - > prepare("insert into `vpb_uploads` (`username`, `firstname`, `lastname`, image_one, image_two, image_three, image_four, image_five, date)values(?,?,?,?,?,?,?,?,?)"); 
    $insert - > bind_param('sssssssss', $username, $wtf, $hello, $random_name_generated, $i2, $i3, $i4, $i5, $date); 
    $insert - > execute(); 
    $identity = "image_one"; 
} else { 
    $get_empty_field = $check_empty_field - > bind_result($username, $wtf, $hello); 
    if(false === $get_empty_field) { 
    die('bind_result() failed: '.htmlspecialchars($mysqli - > error)); 
    } 
    $image_one = strip_tags($get_empty_field["image_one"]); 
    $image_two = strip_tags($get_empty_field["image_two"]); 
    $image_three = strip_tags($get_empty_field["image_three"]); 
    $image_four = strip_tags($get_empty_field["image_four"]); 
    $image_five = strip_tags($get_empty_field["image_five"]); 
    global $identity; 
} 

Answer 1

由於您沒有將從SQL查詢返回的每個列名設置爲變量，因此會引發此錯誤。

例子：

如果你在你的表6列，並選擇了所有（*），那麼你將有：

$stmt->bind_result($Col_1,$Col_2,$Col_3,$Col_4,$Col_5,$Col_6); 

如果您有：

$stmt->bind_result($Col_1,$Col_2,$Col_3,$Col_4,$Col_5); 

一個錯誤將被拋出。

---

$check_empty_field->data_seek(0); 
    $get_empty_field = $check_empty_field - > bind_result($username, $wtf, $hello);