我試着更新我的JPA庫更新查詢與JPA和Java
@Transactional
public interface UserRepository extends JpaRepository<User, Integer> {
User findByUsername(String username);
User findById(Long id);
@Query(value = "update user t set t.rule_id = NULL where t.rule_id = :id", nativeQuery = true)
List<User> setNUll(@Param("id") String id);}
這是我的控制器的一部分:
@RequestMapping(value = "/admin/rule/{id}/edit", method = RequestMethod.GET)
public String editRule(@PathVariable Integer id, Model model)
{
userService.setNUll(Integer.toString(id));
model.addAttribute("rule", ruleCrudService.getRuleById(id));
updateUserData();
return "ruleForm";
}
而且在我的瀏覽器這個錯誤apears:
There was an unexpected error (type=Internal Server Error, status=500). could not extract ResultSet; nested exception is org.hibernate.exception.GenericJDBCException: could not extract ResultSet
服務器還說:
SQL Error: 0, SQLState: S1009 2017-06-18 12:51:15.778 ERROR 10388 --- [nio-8080-exec-4] o.h.engine.jdbc.spi.SqlExceptionHelper : Can not issue data manipulation statements with executeQuery(). 2017-06-18 12:51:15.844 ERROR 10388 --- [nio-8080-exec-4] o.a.c.c.C.[.[.[/].[dispatcherServlet] : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: could not extract ResultSet; nested exception is org.hibernate.exception.GenericJDBCException: could not extract ResultSet] with root cause
java.sql.SQLException:不能使用executeQuery()發出數據操作語句。