Android：如何在彈出窗口中打開WebView？

Question

我已經有一個加載了內容的WebView，我需要選擇文本，這將在彈出窗口中打開一個新的WebView。彈出窗口將包含一個我將提交的表單，當我點擊輸入時，它將保存數據並關閉彈出窗口。在這個階段，我需要通過選擇文本或單擊按鈕來打開WebView彈出窗口。

我曾嘗試回答https://stackoverflow.com/a/9173368/2341601但這種崩潰的應用程序，當我做

WebView wv = new WebView(this); 

logcat的消息：

Process: com.example.user.testapp, PID: 13984 
java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.user.testapp/com.example.user.testapp.MainActivity}: android.util.AndroidRuntimeException: requestFeature() must be called before adding content 
     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2404) 
     at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2464) 
     at android.app.ActivityThread.access$900(ActivityThread.java:172) 
     at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1308) 
     at android.os.Handler.dispatchMessage(Handler.java:102) 
     at android.os.Looper.loop(Looper.java:146) 
     at android.app.ActivityThread.main(ActivityThread.java:5653) 
     at java.lang.reflect.Method.invokeNative(Native Method) 
     at java.lang.reflect.Method.invoke(Method.java:515) 
     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1291) 
     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1107) 
     at dalvik.system.NativeStart.main(Native Method) 

產生的原因：android.util.AndroidRuntimeException：requestFeature（）必須是在添加內容之前調用

Answer 1

final Dialog dialog = new Dialog(context); 
     dialog.requestWindowFeature(Window.FEATURE_NO_TITLE); 
     dialog.setContentView(R.layout.webview_layout); 

WebView wv = (WebView) dialog 
      .findViewById(R.id.webview); 

wv.loadUrl("http:\\www.google.com"); 
wv.setWebViewClient(new WebViewClient() { 
    @Override 
    public boolean shouldOverrideUrlLoading(WebView view, String url) { 
     view.loadUrl(url); 

     return true; 
    } 
}); 

dialog.setOnKeyListener(new OnKeyListener() { 

     @Override 
     public boolean onKey(DialogInterface dialog, int keyCode, 
       KeyEvent event) { 
      if (keyCode == KeyEvent.KEYCODE_BACK) { 

       dialog.dismiss(); 
      } 

      return false; 
     } 
    }); 

webview_layo XML.XML

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    android:layout_width="match_parent" 
    android:layout_height="match_parent" 
    android:orientation="vertical" > 

    <WebView 
     android:id="@+id/webView" 
     android:layout_width="match_parent" 
     android:layout_height="match_parent" /> 

</LinearLayout> 

Answer 2

避免請求未來崩潰。

DialogFragment.java

public class DialogFragment extends android.support.v4.app.DialogFragment { 

private boolean isModal = false; 

public static DialogFragment newInstance() 
{ 
    DialogFragment frag = new DialogFragment(); 
    frag.isModal = true; // WHEN FRAGMENT IS CALLED AS A DIALOG SET FLAG 
    return frag; 
} 


@Override 
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) 
{ 
    if(isModal) // AVOID REQUEST FEATURE CRASH 
    { 
    return super.onCreateView(inflater, container, savedInstanceState); 
    } 
    else 
    { 
    View view = inflater.inflate(R.layout.dialog_webview, container, false); 
    setupUI(view); 
    return view; 
    } 
} 

@Override 
public Dialog onCreateDialog(Bundle savedInstanceState) { 
    AlertDialog.Builder builder = new AlertDialog.Builder(getActivity()); 
    // Get the layout inflater 

    View view = getActivity().getLayoutInflater().inflate(R.layout.dialog_webview, null); 

    builder.setView(view); 
    WebView wv = (WebView) view.findViewById(R.id.webView); 

    wv.loadUrl("http:\\www.google.com"); 
    wv.setWebViewClient(new WebViewClient() { 
     @Override 
     public boolean shouldOverrideUrlLoading(WebView view, String url) { 
      view.loadUrl(url); 

      return true; 
     } 
    }); 
    return builder.create(); 
} 
}